<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
__Data__
The equilateral's lengths are all the same
Also if AB = AD = BD = CD that would mean all those sides have the exact same length
Answers and Explanations
15A. BCD has 2 acute angles and one obtuse angle, so this is an Obtuse Triangle
15B. If beforementioned = 5 cm
Then the perimeter is 5cm x 3 = 15cm
15C. ABC is a Right Triangle
16. abcdef. Measure the angles using a protractor
17. The shortest side of ABC is AB which is 5cm, the longest is AC which is 10cm
Shortest side: Longest side
5cm:10cm
1:2 is the ratio
Answer:
best way would be calendar
Step-by-step explanation:
then stop watch
heartbeat
finding height?
(im not totally sure because it depends what type of timekeeping you're talking about)
