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Svetradugi [14.3K]
3 years ago
15

The 1st flat-bar, or cross, or other operator means: -9-(-7)

Mathematics
1 answer:
babunello [35]3 years ago
7 0

-9-(-7)

-9--7

-9+7

7-9

-2

---

hope it helps

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3² +4² = 5²,
AlekseyPX

Answer:

They are all true

Step-by-step explanation:

1. 3² +4² = 5²

3x3 + 4x4 = 5x5

  9   +  16  =  25

25 = 25

-----------------------

2. 6² + 8² = 10²

36 + 64 = 100

100 = 100

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3. 9² + 12² = 15²

81 + 144 = 225

225 = 225

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4. 5² +12² =13²

25 + 144 = 169

169 =169

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7 0
1 year ago
John is 12 years older than Miles. Five years ago, John was two times as old as Miles was back then. How old are John and Miles
Evgen [1.6K]

Answer:

John is 29, Myles is 17.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
General term for -13, -11, -9, -7
timurjin [86]

The general term for the arithmetic sequence; -13, -11, -9, -7 is Tn = -15 - 2n.

<h3>Arithmetic progression</h3>

-13, -11, -9, -7

  • First term, a = -13
  • Second term = -11

Common difference, d = Second term - first term

= -11 - (-13)

= -11 + 13

= 2

Therefore,

Tn = a + (n - 1)d

Where,

  • n = number of terms

Tn = a + (n - 1)d

= -13 + (n - 1)2

= -13 - 2n - 2

Tn = -15 - 2n

So therefore, the general term for the arithmetic sequence; -13, -11, -9, -7 is Tn = -15 - 2n.

Learn more about arithmetic progression:

brainly.com/question/6561461

#SPJ1

5 0
2 years ago
P³ = 1/8 please help me if anybody can .
ivanzaharov [21]

Answer:

p= \dfrac{1}{2}

Step-by-step explanation:

Given equation:

p^3=\dfrac{1}{8}

Cube root both sides:

\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}

\implies p= \sqrt[3]{\dfrac{1}{8}}

\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:

\implies p= \left(\dfrac{1}{8}\right)^{\frac{1}{3}}

\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:

\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad 1^a=1:

\implies p= \dfrac{1}{8^{\frac{1}{3}}}

Rewrite 8 as 2³:

\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies p= \dfrac{1}{2^{(3 \cdot \frac{1}{3})}}

Simplify:

\implies p= \dfrac{1}{2^{\frac{3}{3}}}

\implies p= \dfrac{1}{2^{1}}

\implies p= \dfrac{1}{2}

3 0
1 year ago
Read 2 more answers
Please show all work and explanation.<br><img src="https://tex.z-dn.net/?f=6%5Cfrac%7B1%7D%7B4%7D-4%5Cfrac%7B3%7D%7B5%7D" id="Te
Olin [163]

Steps:

6 1/4 - 4 3/15 can also be written as 25/4 - 23/5

The LCD of 4 and 5 is 20.

That gives us 125/20 - 92/20.

Now, just subtract the numerators (leave the denominators the same).

That brings us to 33/20, which can be simplified to 1 13/20

Final Answer:

1\frac{13}{20}

--------------------------------------------------------------------------------------------------------------

<u><em>*Please mark brainliest if that helped!*</em></u>

8 0
3 years ago
Read 2 more answers
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