Answer:
Force of friction, f = 751.97 N
Explanation:
it is given that,
Mass of the car, m = 1100 kg
It is parked on a 4° incline. We need to find the force of friction keeping the car from sliding down the incline.
From the attached figure, it is clear that the normal and its weight is acting on the car. f is the force of friction such that it balances the x component of its weight i.e.
f = 751.97 N
So, the force of friction on the car is 751.97 N. Hence, this is the required solution.
Answer:
Blue light has the shortest wavelength amongst all the colours that combine to make white light. This means the blue light diffracts (bends) the most out of all of them. There will be no dispersion of colours because ideally, the blue light must consist of only one frequency.
The average radius(r) of each grain is r = 50 nanometers
= 50*10^-6 meters
Since it is spherical, so
Volume=(4/3)*pi*r^3
V= (4/3)*pi*(50*10^-6)^3
V=5.23599*10^-13 m^3
We are given the Density(ρ) =2600kg/m^3
We know that:
Density(p) = mass(m)/volume(V)
m = ρV
So the mass of a single grain is:
m = 5.23599*10^-13 * 2600 = 1.361357*10^-9 kg
The surface area of a grain is:
a = 4*pi*r^2
a = 4*pi*(50*10^-6)^2
a = 3.14*10^-8 m^2
Since we know the surface area and mass of a grain, the
conversion factor is:
1.361357*10^-9 kg / 3.14*10^-8 m^2
Find the Surface area of the cube:
cube = 6a^2
cube = 6*1.1^2 = 7.26m^2
multiply this by the converions ratio to get:
total mass of sand grains = (7.26 m^2 * 1.361357*10^-9 kg)
/ (3.14*10^-8 m^2)
total mass of sand grains = 0.3148 kg = 314.80 g
Answer:
Period, T = 10.86 seconds
Frequency, f = 0.092 Hz
Wavelength,
Speed, v = 3.61 m/s
Explanation:
It is given that,
A woman notices that a wave crest passes by, five more crests pass in a time of 54.0
.
The distance between two successive crests is, the wavelength of wave,
(b)Frequency of a wave is given by number of oscillations per second such that,
f = 0.092 Hz
(a) Let T is the period of the wave. It is inverse of frequency of a wave such that,
T = 10.86 seconds
(c) The distance between two successive crest or trough is called wavelength of a wave, .
(d) The speed of a wave is given by :
v = 3.61 m/s
Hence, this is the required solution.
Answer:
Radial force component of force = 37.68 N
Explanation:
By Newton's 2 nd law of motion,
F = ma
F = 3.0 N, m = 0.5 Kg, a (Linear Acceleration ) = ?
3 = 0.5 a
a = 6
Now, a = 6 , r = 2.5 m ,α(angular acceleration ) = ?
a = r α
6= 2.5 α
hence α = 2.4 rad/
we know that,
Radial force component of force =
since m =0.5 kg, r =2.5 m w =5.49 rad/sec
Radial force component of force = = 37.68 N