Answer:
F=50kg
D=5m
W=FD
therefore work done is 250Nm
When light enters a lens, C) it is refracted.
Since it is bent when it enters a lens, it has to be refracted.
To develop this problem it is necessary to apply the concepts related to the Cross Product of two vectors as well as to obtain the angle through the magnitude of the angles.
The vector product between the Force and the radius allows us to obtain the torque, in this way,





Therefore the torque on the particle about the origen is 50k
PART B) To find the angle between two vectors we apply the definition of the dot product based on the vector quantities, that is,





Therefore the angle between the ratio and the force is 103.88°
We use only one variable at a time to find the accurate result. We want to see how the result of experiment changes everytime with a single variable.
Answer:
angular frequency of the table must be same as the frequency of the projection of the gum on the wall
Explanation:
Since we know that the projection on the wall is the vertical component of the position of the gum on the rotating table
So here we will say

so the angle made by the radius vector depends on the angular frequency of the disc by which it is rotating
So we can say

so here we can say

so here we can say that
angular frequency of the table must be same as the frequency of the projection of the gum on the wall