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3 years ago

What is a factor of each term of the polynomial?. (3d2 – 10d).

Mathematics

2 answers:

finlep [7]3 years ago

7 0

Answer:

$d(3d-10)$ is the factor term of given polynomial.

Step-by-step explanation:

We have been given an expression:

$3d^2-10d$

We will take the common term out of the given expression which is d

Hence, we get:

$d(3d-10)$

We have been asked the factor term of the polynomial:

Therefore, the factor term of the polynomial is: $d(3d-10)$

shepuryov [24]3 years ago

4 0

(3d^2 - 10d) = d(3d - 10).

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A study is designed to determine whether grades in a statistics course could be improved by offering special review material. Th

mr Goodwill [35]

Answer:

Experimental but not double-blinded study

Step-by-step explanation:

The type of study being described is an Experimental but not double-blinded study. That is because it is a study that has a control group, dependent variable, and an independent variable all used in order to acquire specifically targetted data from the results that are derived from the experiment itself. Also since the scientists/researchers know exactly which lab sections are getting the extra review material (independent variable), then that makes this a non-double-blinded study.

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3 years ago

Hi everyone , Would you help me please :

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3 years ago

At the market, Ms. Winn bought 3/4 lb of grapes and 5/8 lb of cherries.

wolverine [178]

Answer:

Part a) Ms. Winn bought 12 oz of grapes

Part b) Ms. Winn bought 10 oz of cherries

Part c) Ms. Winn bought 2 oz more of grapes than cherries

Part d) Mr. Phillips bought 6 more ounces of fruit than Ms. Winn

Step-by-step explanation:

Part a) How many ounces of grapes did Ms. Winn buy?

Remember that

$1\ lb=16\ oz$

To convert lb to oz multiply by 16

we know that

Ms. Winn bought 3/4 lb of grapes

Convert lb to oz

Multiply by 16

$\frac{3}{4}\ lb= \frac{3}{4}(16)=12\ oz$

therefore

Ms. Winn bought 12 oz of grapes

Part b) How many ounces of cherries did Ms. Winn buy?

Remember that

$1\ lb=16\ oz$

To convert lb to oz multiply by 16

we know that

Ms. Winn bought 5/8 lb of cherries

Convert lb to oz

Multiply by 16

$\frac{5}{8}\ lb= \frac{5}{8}(16)=10\ oz$

therefore

Ms. Winn bought 10 oz of cherries

Part c) How many more ounces of grapes than cherries did Ms. Winn buy?

Subtract the ounces of cherries from the ounces of grapes

$12\ oz-10\ oz=2\ oz$

therefore

Ms. Winn bought 2 oz more of grapes than cherries

Part d) If Mr. Phillips bought 1 3/4 pounds of raspberries, who bought more fruit, Ms. Winn or Mr. Phillips? How many ounces more?

Remember that

$1\ lb=16\ oz$

To convert lb to oz multiply by 16

we know that

Mr. Phillips bought 1 3/4 pounds of raspberries

Convert mixed number to an improper fraction

$1\frac{3}{4}\ lb=\frac{1*4+3}{4}=\frac{7}{4}\ lb$

Convert lb to oz

Multiply by 16

$\frac{7}{4}\ lb= \frac{7}{4}(16)=28\ oz$

Remember that

Ms. Winn bought 12 oz of grapes and 10 oz of cherries

In total Ms. Winn bought

12 oz+10 oz=22 oz -----> total ounces of fruit

Mr. Phillips bought 28 oz of fruit

Ms. Winn bought 22 oz of fruit

$28\ oz > 22\ oz$

Find the difference

$(28\ oz-22\ oz)=6\ oz$

therefore

Mr. Phillips bought 6 more ounces of fruit than Ms. Winn

4 0

3 years ago

Wayne Gretsky scored a Poisson mean six number of points per game. sixty percent of these were goals and forty percent were assi

BartSMP [9]

Answer:

a) The mean for the total revenue he earns per game is of 13.2K while the standard deviation is of 3.63K.

b) 0.05 = 5% probability that he has four goals and two assists in one game

Step-by-step explanation:

In hockey, a point is counted for each goal or assist of the player.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval. The standard deviation is the square root of the mean.

(a) Find the mean and standard deviation for the total revenue he earns per game.

60% of six are goals, which means that 60% of the time he earned 3K.

40% of six are goals, which means that 40% of the time he earned 1K.

The mean is:

$\mu = 6*0.6*3 + 6*0.4*1 = 13.2$

The standard deviation is:

$\sigma = \sqrt{\mu} = \sqrt{13.2} = 3.63$

The mean for the total revenue he earns per game is of 13.2K while the standard deviation is of 3.63K.

(b) What is the probability that he has four goals and two assists in one game

Goals and assists are independent of each other, which means that we find the probability P(A) of scoring four goals, the probability P(B) of getting two assists, and multiply them.

Probability of four goals:

60% of 6 are goals, which means that:

$\mu = 6*0.6 = 3.6$