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kondaur [170]
3 years ago
12

In an experiment to create a pendulum, each member of the group measured the length of the string to be a slightly different val

ue. How do we describe these small differences when reporting the length?
Physics
1 answer:
svetlana [45]3 years ago
4 0

Answer:Kobe

Explanation:

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What is the index of retraction?
poizon [28]

Light bends when it travels from a certain density of matter into a different density of matter. The density of the stuff affects how much it bends. Light bends when it transitions from air to water or from water to air. Light bends when it travels from water to glass or from glass to air. How much light is bent by a particular substance may be determined by its index of refraction. However, Snell's Law and the angle of incidence must be coupled. The angle of refraction increases with increasing angle of incidence. As a result, the water's unique index of refraction bends light entering the medium at an angle of 30°. and that is 1.33.  This means that light in a vacuum travels at 1.33 times faster than light in water. We wouldn't have lenses in the way we do now without refractive index. We would need eyes with pinhole-sized openings in order to see, which would prevent us from seeing clearly or at least in great detail. We wouldn't have had microscopes to view anything in great detail, telescopes to view the moon, planets, or distant things. I could go on, but I think you get the idea: if we didn't have the material characteristic known as refraction, things would be quite different. Well, I guess it's possible that human eyes have evolved to have diffractive lenses, but that's another theory.

________________________

The ability of a substance, whether it is solid, liquid, or gas, to reflect light causes it to move more slowly than it would in a vacuum.

Any substance's refractive index (n) is found by dividing the speed of light in that substance by the speed of light in a vacuum (c) (v).

So

n = c/v

Since a material's refractive index varies depending on the wavelength of light, n = f(wavelength) (n is a function of wavelength). In comparison to longer wavelengths, the index is larger for shorter wavelengths. It's known as dispersion.

When creating lenses or other refractive optical systems, the refractive index and dispersion are both crucial factors. The diverse wavelengths don't come to a common focus, which has a disastrous effect on image quality because index is directly related to how light bends while passing through a lens. We refer to this as chromatic aberration. It's difficult to regulate, but you can achieve it by carefully selecting various glass chemistries and massaging them into position. The glass map showing index as a function of inverse dispersion is seen in the image below. About 20 to 100 is the range of the Abby number, a measure of dispersion; lower numbers indicate more dispersion (larger index difference between red and blue light). Every dot stands for a distinct glass.

Refractive indices range from 1.0003 for air, to over 4.5 for Geranium.

3 0
2 years ago
(b) When petrol passes through a delivery pipe, electrostatic charge can build up as shown in the diagram.
Gre4nikov [31]
The answer is, If you're walking on the ice cream at 5 ounces per toaster, and your bicycle loses a sock, how much gravy will you need to repaint your hamster?
6 0
3 years ago
Which of the waves has the smallest amplitude?
balandron [24]

Answer:

I think its the Blue wave, im not sure so dont take my word for it.

Explanation:

3 0
3 years ago
Unpolarized light passes through a combination of two ideal polarizers. The transmission axes of the first polarizer and the sec
Yuliya22 [10]

Answer:

62.5 %

Explanation:

Let the initial intensity of unpolarized light is Io.

After first polariser the intensity of light becomes I'.

So, I' = \frac{I_{0}}{2}

Now it passes through another polariser. The angle between the first polariser and the second polariser is given by Ф. The intensity is I''.

According to the law of Malus

I'' = I' Cos^{2}\phi

Here, Ф = 30 degree

I'' = \frac{I_{0}}{2} Cos^{2}30=0.375I_{0}

The percentage change in the intensity is given by

\frac{I_{0}-I''}{I_{0}}\times 100=\frac{I_{0}-0.375I_{0}}{I_{0}}\times100

= 62.5 %

7 0
3 years ago
If an X-ray beam of wavelength 1.4 × 10-10 m makes an angle of 20° with a set of planes in a crystal causing first order constru
Flura [38]

Answer:

43.16°

Explanation:

λ = Wavelength = 1.4×10⁻¹⁰ m

θ₁ = 20°

n can be any integer

d = distance between the two slits

Since for the first bright fringe, n₁ = 1

n₂ = 2 for second order line

The relation between the distance of the slits and the angle through which it is passed is:

dsinθ=nλ

As d and λ are constant

\frac{n_1\lambda}{sin \theta_1}=\frac{n_2\lambda}{sin \theta_2}\\\Rightarrow \frac{1}{sin20}=\frac{2}{sin\theta_2}\\\Rightarrow sin\theta_2=\frac{2}{\frac{1}{sin20}}\\\Rightarrow \theta_2=sin^{-1}{\frac{2}{\frac{1}{sin20}}}\\\Rightarrow \theta_2=43.16^{\circ}

∴ Angle by which the second order line appear is 43.16°

5 0
3 years ago
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