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3 years ago

9

(b) When petrol passes through a delivery pipe, electrostatic charge can build up as shown in the diagram.

1 answer:

Gre4nikov [31]3 years ago

6 0

The answer is, If you're walking on the ice cream at 5 ounces per toaster, and your bicycle loses a sock, how much gravy will you need to repaint your hamster?

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What does NOT experience gravity?

marissa [1.9K]

Answer:

Astronauts who are orbiting the Earth often experience sensations of weightlessness. These sensations experienced by orbiting astronauts are the same sensations experienced by anyone who has been temporarily suspended above the seat on an amusement park ride. Not only are the sensations the same (for astronauts and roller coaster riders), but the causes of those sensations of weightlessness are also the same. Unfortunately however, many people have difficulty understanding the causes of weightlessness.

6 0

3 years ago

List two pieces of evidence<br> related to this picture

tatyana61 [14]

Answer:

there was a crash you can tell cause of the 2 cars the dog is curious on what happened, you can tell because the dog is looking at the cash

4 0

3 years ago

Read 2 more answers

Rgfffffffffffffffffffffffffffffffffffffffffffffffffffffff

goblinko [34]

Roygbv evjnefvvnefv ekfv k kn ke nv

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3 years ago

A uniform meter stick is pivoted at the 50.00 cm mark on the meter stick. A 400.0 gram object is hung at the 20.0 cm mark on the

babunello [35]

Answer:C

Explanation:

Given

mass $m_1=400\ gm$ is at $x=20\ cm$ mark

mass $m_2=320\ gm$ is at $x=75\ cm$ mark

Scale is Pivoted at $x=50\ cm mark$

For scale to be in equilibrium net torque must be equal to zero

Taking ACW as positive thus

$T_{net}=0.4\times g\times (0.5-0.2)-0.32\times g\times(0.75-0.50)$

$T_{net}=0.12g-0.08g=0.04g$

Therefore a net torque of 0.04 g is required in CW sense which a mass $400\ gm$ can provide at a distance of $x_o$ from pivot

$0.04g=0.4\times g\times x_o$

$x_o=0.1\ m$

therefore in meter stick it is at a distance of $x=60\ cm$

6 0

3 years ago

An object experiences an acceleration of 6.8m/s2.As a result,it accelerates from rest to 24m/s.How much distance did it travel d

Hitman42 [59]

The distance covered by the object is 42.4 m

Explanation:

The motion of the object is a uniformly accelerated motion (at constant acceleration), therefore we can use the following suvat equation:

$v^2 -u^2 = 2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the object in this problem, we have:

u = 0 (it starts from rest)

v = 24 m/s (final velocity)

$a=6.8 m/s^2$

Solving for s, we find the distance travelled by the object:

$s=\frac{v^2-u^2}{2a}=\frac{24^2-0}{2(6.8)}=42.4 m$

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

8 0

3 years ago