Answer:
Tia cut a 4-meter 8-centimeter wire into 10 equal pieces. for Jay 10 quarts would be the answer. Step-by-step explanation: He needs x quarts for the inside painting and x + 19 quarts for the outside. These two measures add up to 2x + 19, which equals 107 (quarts) total. The last one is tring A is 35 cm long, string B is 5 times as long as string A, then string B is 35·5=175 cm long. In total both strings have length 35+175=210 cm. The total length of string needed for 17 identical decirative bottes is cm that is 35.7 m.
Answer:
3
√
2
Explanation:
First put change the words into an equation:
√
3
×
√
6
Now you can multiply them together as you would normally multiply:
√
3
×
√
6
=
√
18
Now let's prime factor 18 and see if there are any squares that we can take out of it to simplify. All we have to see is if there are 2 numbers that are the same:
18
/ \
6
3
/ \
2
3
As you can see, we have a square:
3
×
3
=
9
So take
√
9
out of
√
18
. You should have:
√
9
√
2
But since
√
9
=
3
we can simplify further to make:
√
9
√
2
→
3
√
2
Step-by-step explanation:
Answer:
y = 2/3x + 1
Step-by-step explanation:
<u>3y = 2x + 3 </u> Divide all by 3
3 3 3
y = 2/3x + 1 Slope is 2/3
10 students (brass)=40% of band
4 students (strings)=16% of band
? students (other)=44% rest of band
14/56%=?/44%
(cross multiply to find ?){don't forget to turn percents into decimals}
?=11
There are 25 students in total in the band.
Answer:
The point of maximum growth is at x=0.82
Step-by-step explanation:
Given a logistic function
we have to find the point of maximum growth rate for the logistic function f(x).
From the graph we can see that the carrying capacity or the maximum value of logistic function f(x) is 24 and the point of maximum growth is at 
i.e between 0 to 12
So, we can take and then solve for x.
⇒ 
⇒ 
⇒ 
⇒ log 3=-1.3x
⇒ -0.4771=-1.3.x ⇒ x=0.82
Hence, the point of maximum growth is at x=0.82
