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yaroslaw [1]
3 years ago
8

Please helppppp meeeeeee!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
astraxan [27]3 years ago
6 0

Answer:option A is the correct answer.

Step-by-step explanation:

The given triangle UVW is a right angle triangle. This is because one of its angles is 90 degrees. The sum of the two other angles is 180. To determine Cos U, we will apply trigonometric ratio.

Cos U = adjacent side/ hypotenuse.

Looking at the triangle with C as the reference angle,

Adjacent side = 12

Hypotenuse( always the longest side of the triangle) = 13

Therefore,

Cos U = 12/13

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A farmers field has the dimensions 2 and 3/4 by 1 and 1/3. He needs to find the area of the field
Afina-wow [57]

Answer:

3 2/3 units²

Step-by-step explanation:

Since the field is rectangular in nature;

Area of the field = Length * Width

Given

Length = 2 3/4

Width = 1 1/3

Area of the field = 2 3/4 * 1 1/3

Area of the field = 11/4 * 4/3

Area of the field = 4/4 * 11/3

Area of the field = 1 * 11/3

Area of the field = 11/3

Area of the field = 3 2/3

Hence the area of the field is 3 2/3 units²

5 0
3 years ago
If you vertically stretch the absolute value parent function, f(x) = |x|, by a factor of 5, which is the equation of the new fun
faltersainse [42]
I believe it is f(x)=5|x|
I suggest you get a second opinion, though
3 0
3 years ago
{ (1, 1) , (19, 88) , (-3, -5) , (1/2 , -3) , (100, 101) , (200, 9) , (0, -33) }
yuradex [85]

Answer:

i try my best to find the answer and then i will tell just give me some time

Step-by-step explanation:

4 0
2 years ago
Sherman has two sequences . The first sequence is described by the explicit rule f(n) = 15n + 4 and the second sequence is descr
Viktor [21]

Answer:

Step-by-step explanation:

Given the explicit function as

f(n) = 15n+4

The first term of the sequence is at when n= 1

f(1) = 15(1)+4

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 15(2)+4

f(2) = 34

d = 34-19

d = 15

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)15)

S20 = 10(38+19(15))

S20 = 10(38+285)

S20 = 10(323)

S20 = 3230.

Sum of the 20th term is 3230

For the explicit function

f(n) = 4n+15

f(1) = 4(1)+15

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 4(2)+15

f(2) = 23

d = 23-19

d = 4

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)4)

S20 = 10(38+19(4))

S20 = 10(38+76)

S20 = 10(114)

S20 = 1140

Sum of the 20th terms is 1140

7 0
3 years ago
Min has a shelf filled with books. The books have different thicknesses. This line plot shows the thickness of each book. He pil
Vladimir [108]

Answer:

$2\frac{1}{4} \ inch$

Step-by-step explanation:

We have the four thickest books from the line plot given by

Two books of $\frac{1}{2}$ inch thick and the two books of $\frac{5}{8}$ inch thickness.

So when the two $\frac{1}{2}$ inch thick book is being piled on the top of a $\frac{5}{8}$ inch thick books.

Therefore, the total thickness of the pile of books is given by :

$=2 \times \frac{1}{2}+2 \times \frac{5}{8}$

$=\frac{9}{4}$

$=2\frac{1}{4} \ inch$

Therefore, the thickness of the pile is $2\frac{1}{4} \ inch$ .

7 0
3 years ago
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