answer : False
The measure of a tangent-tangent angle is one - half the difference of the measures of the intercepted arcs.
The diagram is attached below
AB and BC are the two tangents
By exterior angle theorem
∠3 = ∠2 + ∠4
So ∠2 = ∠3 - ∠4
Now we find angle 3 and 4, we know when a chord and tangent intersect at a point then the measure of angle is one half of measure of intercepted arc
∠3 = 
∠4 = 
∠2 = ∠3 - ∠4
∠2 = -
∠2 = 
The measure of a tangent-tangent angle is one half the difference of the measures of the intercepted arcs.
Answer:
f(4)=47
Step-by-step explanation:
To find the answer, replace the x’s in the equation with 4. This would make the equation 3(4)^2 + 4 - 5. According to PEMDAS, you would first raise 4 to the power of 2 (16) then multiply it by 3 (48). This makes the equation 48 + 4 - 5. You just need to add and subtract from here. 48+4=52. 52-5=47
Answer:
5^12
Step-by-step explanation:
index notation rules states that when there is a power inside AND outside the brackets, they shall multiply together. hence, we will multiply 3 and 2 so we will get 6 and thus the answer will be 5^6. Sike, that's not the answer, we forgot to multiply 5 with that power too... so we will get 25^6 because same power (outside brackey) will affect everything inside...
now after we got 25^6, we need to simplify it to get 5^n ....
so as we know 5^2 is 25, we can do this,
(5^2)^6 so we will multiply the powers to get
5^12 which is your answer :)
pls mark this as brainliestttt
The answer is A, hope i helped. Mark me as brainliest?
Answer:
X=3 and X=2 eassyyyy
Step-by-step explanation:
have a good day
