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2 years ago

Only help me with number 5 plz

Mathematics

2 answers:

Nataly_w [17]2 years ago

6 0

Answer:

perpendicular, parallel

Step-by-step explanation:

Also your answer for #4 is wrong, it's actually line FD

blsea [12.9K]2 years ago

4 0

Answer:

Line AB is Perpendicular to line CD

Line AB Parallel to line EF

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You invest $3,200 in an account that pays an interest rate of 7.25%, compounded continuously. Calculate the balance of your acco

a_sh-v [17]

I=prt
i=(3200)(7.25)(12)
i=278400
p+i=$281600

6 0

2 years ago

X-1/x-2+x+3/x-4=2/(x-2).(4-x)

Varvara68 [4.7K]

The given equation x-1/x-2+x+3/x-4=2/(x-2).(4-x) is correct. the answer is proved.

According to the statement

we have given that the equation and we have to prove that the given answer is a correct answer for those equivalent equation.

So, The given expression are:

$\frac{x-1}{x-2} +\frac{x+3}{x-4} = \frac{2}{(x-2).(4-x)}$

And we have to prove the answer.

So, For this

$\frac{x-1}{x-2} +\frac{x+3}{x-4}$

$\frac{({x-1}) ({x-4}) +({x+3})({x-2})} {(x-2) (x-4)}$

Then the equation become

$\frac{x^{2} -4x -x +4 + x^{2} -2x + 3x -6 }{(x-2) (x-4)}$

Now solve it then

$2x^{2} - 4x -2 / (x-2) (x-4)$

Now take 2 common from answer then equation become

$\frac{x-1}{x-2} +\frac{x+3}{x-4} = \frac{2}{(x-2).(4-x)}$

Hence proved.

So, The given equation x-1/x-2+x+3/x-4=2/(x-2).(4-x) is correct. the answer is proved.

Learn more about equations here

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3 0

11 months ago

Find the value of y such that the distance between the given points is indicated..... (5,y) and (8,-1) is 5.

maw [93]

(5,y)(8,-1)
d = sqrt ((x2 - x1)^2 + (y2 - y1)^2)
d = sqrt ((8 - 5)^2 + (-1 - y)^2)
d = sqrt (3^2 + (-1 - 3)^2
d = sqrt (9 + (-4^2)
d = sqrt (9 + 16)
d = sqrt 25
d = 5

so ur points are : (5,-3)(8,-1)

6 0

3 years ago

Rewrite the expression with a rational exponent as a radical expression.

Nuetrik [128]

Answer:

Rewriting the expression $(3^\frac{2}{3})^\frac{1}{6}$ with a rational exponent as a radical expression we get $\mathbf{\sqrt[9]{3} }$

Step-by-step explanation:

We need to rewrite the expression $(3^\frac{2}{3})^\frac{1}{6}$ with a rational exponent as a radical expression.

The expression given is:

$(3^\frac{2}{3})^\frac{1}{6}$

First we will simply the expression using exponent rule $(a^m)^n=a^{mn}$

$(3^\frac{2}{3})^\frac{1}{6}\\=(3^\frac{2}{18})$

As we know 2 and 18 are both divisible by 2, we can write

$=(3^\frac{1}{9})$

Now we know that $a^\frac{1}{9}=\sqrt[9]{a}$

Using this we get

$=\sqrt[9]{3}$

So, rewriting the expression $(3^\frac{2}{3})^\frac{1}{6}$ with a rational exponent as a radical expression we get $\mathbf{\sqrt[9]{3} }$

3 0

3 years ago

The standard length of film on a reel is 400 meters. On the first day of shooting a movie, a director

Over [174]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers