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xxTIMURxx [149]
3 years ago
13

I want to wrap an oatmeal container. It is round with two round bases. How much paper would I need to

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
8 0

Answer:

191.9

Step-by-step explanation:

so the actual equation is S=2\pi r^{2} +2\pi rh I know it is confusing but we just learned this so hope this helps!

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BRAINLIEST
Leona [35]

Answer:

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Step-by-step explanation:

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3 years ago
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Differentiate x^2 e^x logx
zimovet [89]

Product rule:

\dfrac{\mathrm d}{\mathrm dx}(x^2e^x\log x)

=\dfrac{\mathrm d(x^2)}{\mathrm dx}e^x\log x+x^2\dfrac{\mathrm d(e^x)}{\mathrm dx}\log x+x^2e^x\dfrac{\mathrm d(\log x)}{\mathrm dx}

Power rule:

\dfrac{\mathrm d(x^2)}{\mathrm dx}=2x

The exponential function is its own derivative:

\dfrac{\mathrm d(e^x)}{\mathrm dx}=e^x

Assuming the base of \log x is e, its derivative is

\dfrac{\mathrm d(\log x)}{\mathrm dx}=\dfrac1x

But if you mean a logarithm of arbitrary base b, we have

y=\log_bx\implies x=b^y=e^{y\ln b}\implies1=e^{y\ln b}\ln b\dfrac{\mathrm dy}{\mathrm dx}

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{e^{-y\ln b}}{\ln b}=\dfrac1{b^y\ln b}

\implies\dfrac{\mathrm d(\log_bx)}{\mathrm dx}=\dfrac1{x\ln b}

So we end up with

2xe^x\log x+x^2e^x\log x+\dfrac{x^2e^x}x

=xe^x(2\log x+x\log x+1)

8 0
3 years ago
Z2 + (2j – 3)z + (5 – j) = 0
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Answer:

2z+(2j-3)z+(5-j)=0

2z +2jz-3z+5-j=0

2z-3z+2jz-j=-5

-z+2jz-j=-5

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I hope this help

4 0
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5) A rectangular piece of paper is 10cmn long and 5cm broad.find its area,​
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Area=L•W
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