Solubility<span> is a chemical property referring to the ability for a given substance, the solute, to dissolve in a solvent. It has units of grams of the substance per grams of solvent. We calculate the mass as follows:
311 g AgNO3 / 100 g water (350 g water) = 1088.5 g AgNO3
It can be rounded of to 1100 g of AgNO3. Therefore, option B is the correct answer.</span>
- If the abundance of the first isotope is 68.037%, then the abundance of the second isotope is 100%-68.037%.
Substituting into the atomic mass formula,
I attached the working and the answer to the question below.
Please note that in the formula, C = speed of light, ν = frequency, λ= wavelength
<span>
The wavelength of a 2.80 Hz wave is
1.07 </span>
× 10¹⁰
cm.
Answer:
552 g of LiNO₃
Explanation:
From the question given above, the following data were obtained:
Volume of solution = 2 L
Molarity of LiNO₃ = 4 M
Mass of LiNO₃ =?
Next, we shall determine the number of mole of LiNO₃ in the solution. This can be obtained as follow:
Volume of solution = 2 L
Molarity of LiNO₃ = 4 M
Mole of LiNO₃ =?
Molarity = mole /Volume
4 = mole of LiNO₃ / 2
Cross multiply
Mole of LiNO₃ = 4 × 2
Mole of LiNO₃ = 8 moles
Finally, we shall determine the mass of of LiNO₃ needed to prepare the solution. This is can be obtained as follow:
Mole of LiNO₃ = 8 moles
Molar mass of LiNO₃ = 7 + 14 + (16×3)
= 7 + 14 + 48
= 69 g/mol
Mass of LiNO₃ =?
Mole = mass /Molar mass
8 = Molar mass of LiNO₃ /69
Cross multiply
Molar mass of LiNO₃ = 8 × 69
Molar mass of LiNO₃ = 552 g
Thus, 552 g of LiNO₃ is needed to prepare the solution.
