Answer:
Empirical formula is CaSO₄.
Explanation:
Given data:
Percentage of calcium =29.44%
Percentage of sulfur = 23.55%
Percentage of oxygen = 47.01%
Empirical formula = ?
Solution:
Number of gram atoms of Ca = 29.44 / 40 = 0.74
Number of gram atoms of S = 23.55 / 32 = 0.74
Number of gram atoms of O = 47.01 / 16 = 3
Atomic ratio:
Ca : S : O
0.74/0.74 : 0.74/0.74 : 3/0.74
1 : 1 : 4
Ca : S : O = 1 : 1 : 4
Empirical formula is CaSO₄.
The answer is the reaction ins a cold pack
What is the correct name for the cyclic alkane shown on the right? 1,3-dimethyl, 3-ethylcyclohexane 1-ethyl, 1,4-dimethylcyclohexane 1-ethyl-1,3-dimethylcyclohexane 1-ethyl-1,3-dimethylcyclopentane 1,3 dimethyl, 3- ethylcyclopentane A
3. 4 g of a nonelectrolyte dissolved in 78. 3 g of water produces a solution. The molar mass of the solute will be 17.94.
<h3>
What is molar mass?</h3>
Molar mass of a substance is its mass in grams in per mole of a solution.
Freezing point: Freezing point of a substance is a temperature at which a liquid starts to solidify.
Depression in the freezing point can be calculated
[Depression in freezing point of pure solvent—Freezing point of solution] =[(0) - (-4.5)] °C =4.5 °C
molar mass = Number of moles of solute m / Mass of solvent in Kg
3.4g / M x 1/ 0.0783 kg = 43.42
Substitute AT by 4.5°C , Kr by 1.86 °C/m, and m by 43.42 m in equation (1) as follows:
1.86 x 43.42 / 4.5 = 17.94
Therefore, molar mass of solute to be 17.94.
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Answer:
mass is a measure of the amount of matter in a sample or object. It is measured in grammes or kilogrammes
