There are 180 numbers which are three-digit multiples of 5.
According to the statement
we have to find the three digit numbers which are multiples of 5.
we know that three digit numbers are start from 100 to 999 and in 1 line of counting means 100 to 110 there are 2 numbers are multiples of 5.
Here we use Multiplication method to find the number of digit which are a multiple of 5.
It means there are two numbers which are multiples of 5 in the one line of counting and there are 90 lines of counting from 100 to 999.
So, it means the answer will become
2*90 = 180.
So, There are 180 numbers which are three-digit multiples of 5.
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I just know the greatest common factor is 2ab
But i don’t know if it is foil method but I still don’t know how to put it in that format
Answer: x = 6 y = 5
Step-by-step explanation: coz I juss know
Answer:
u = 1
Step-by-step explanation:
