M
350 mL = 0.350 L
245.0g H2SO4 / 98.08 g/mol H2SO4
= 2.5 mol H2SO4
2.5 mol H2SO4 / 0.350 L = 7.14 M
Answer:
The ion will repel the substance because it has lost two electrons.
Explanation:
An ion is a charged specie. We can see from the question that the ion has twelve positive and ten negative particles.
If there are more positive particles than negative particles, then the ion is positively charged.
If the ion is positively charged, it will repel another positively charged particle because like charges repel while opposite charges attract.
Answer:
d. 114.8 u
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
<u>For first isotope:
</u>
% = 95.72 %
Mass = 114.9041 u
<u>
For second isotope:
</u>
Since the element has only 2 isotopes, so the percentage of second is 100 - first percentage.
% = 100 % - 95.72 % = 4.28 %
Mass = 112.9043 u
Average Mass = ?
Thus,
<u>Average atomic mass = 114.8 u</u>
Answer:
The amount of heat released by the combustion of 2 moles of methane = 1605.1 kJ
Option 3 is correct.
ΔH°(combustion of 2 moles of methane)
= -1,605.1 kJ
Explanation:
The balanced equation for the combustion of methane is presented as
CH₄ + 2O₂ → CO₂ + 2H₂O
The heat of formation for the reactants and products are
CH₄ (g): ΔHf = –74.6 kJ/mol;
CO₂ (g): ΔHf = –393.5 kJ/mol;
and H₂O(g): ΔHf = –241.82 kJ/mol.
ΔHf for O₂ = 0 kJ/mol
ΔH°rxn for the combustion of methane is given as
ΔH°rxn = ΣnH°(products) - ΣnH°(reactants)
ΣnH°(products) = (1×-393.5) + (2×-241.82)
= -877.14 kJ/mol
ΣnH°(reactants) = (1×-74.6) + (2×0)
= -74.6 kJ/mol
ΔH°rxn = -877.14 - (-74.6) = -802.54 kJ/mol
For 2 moles of methane, the heat of combustion = 2 moles × -802.54 kJ/mol
= -1,605.08 kJ = -1,605.1 kJ
Hope this Helps!!!
The answer for this would be 69.6