The molality of a solution containing 8.1 moles of solute in 4847 g of solvent is ____.
2 answers:
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Answer:
Explanation:
Pair 2.50g of O₂ and 2.50g of N₂
The atoms sample with the largest number of moles since the masses are the same would be the one with lowest molar mass according the the equation below:
Number of moles =
Atomic mass of O = 16g and N = 14g
Molar mass of O₂ = 16 x 2 = 32gmol⁻¹
Molar mass of N₂ = 14 x 2 = 28gmol⁻¹
Number of moles of O₂ = = 0.078mole
Number of moles of N₂ = = 0.089mole
We see that N₂ has the largest number of moles
Answer:
1027.62 g
Explanation:
For :-
Mass of = 296.1 g
Molar mass of = 27.66 g/mol
The formula for the calculation of moles is shown below:
Thus,
From the balanced reaction:-
1 mole of react with 3 moles of oxygen
Thus,
10.705 mole of react with 3*10.705 moles of oxygen
Moles of oxygen = 32.115 moles
Molar mass of oxygen gas = 31.998 g/mol
<u>Mass = Moles * Molar mass = 32.115 * 31.998 g = 1027.62 g</u>