<u>Answer:</u> The volume of iron is 
<u>Explanation:</u>
To calculate volume of a substance, we use the equation:
We are given:
Mass of iron = 52.6 lbm = 23.86 kg (Conversion factor: 1 kg = 2.205 lbm)
Density of iron = 
Putting values in above equation, we get:
Hence, the volume of iron is
Ocean acidification refers to a reduction in the pH of the ocean over an extended period of time, caused primarily by the uptake of carbon dioxide (CO2) from the atmosphere.
Because of human-driven increased levels of carbon dioxide in the atmosphere, there is more CO2 dissolving into the ocean. The ocean's average pH is now around 8.1, which is basic (or alkaline), but as the sea continues to absorb more CO2, the pH decreases and the ocean becomes more acidic.
How does ocean acidification affect us?
Ocean acidification can modify the abundance and chemical composition of harmful algal blooms in such a way that shellfish toxicity increases and, therefore, human health are negatively affected.
How we can reduce ocean acidification?
The most effective way to limit ocean acidification is to act on climate change, implementing solutions to dramatically reduce the use of fossil fuels. If we dramatically cut our global warming emissions, and we limit future warming, we can significantly reduce the harm to marine ecosystems.
To know more about ocean acidification:
brainly.com/question/7604502
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Answer:
H₂O.
Explanation:
- It is clear from the balanced equation:
<em>CH₄ + 2H₂O → CO₂ + 4H₂.</em>
that 1.0 mole of CH₄ reacts with 2.0 moles of H₂O to produce 1.0 mole of CO₂ and 4.0 moles of H₂.
- To determine the limiting reactant, we should calculate the no. of moles of (20 g) CH₄ and (15 g) H₂O using the relation:
<em>n = mass/molar mass</em>
<em></em>
no. of moles of CH₄ = mass/molar mass = (20 g)/(16 g/mol) = 1.25 mol.
no. of moles of H₂O = mass/molar mass = (15 g)/(18 g/mol) = 0.833 mol.
- <em>from the balanced reaction, 1.0 mole of CH₄ reacts with 2.0 moles of H₂O.</em>
So, from the calculated no. of moles: 0.4167 mole of CH₄ reacts completely with 0.833 mole of H₂O and the remaining of CH₄ will be in excess.
<u><em>So, the limiting reactant is H₂O.</em></u>
Answer:
the answer is very correct as AgNO3 and Cu(NO3)2
Answer:
The total pressure of the mixture in the tank of volume 6.25 litres at 51°C is 1291.85 kPa.
Explanation:
For N2,
Pressure(P₁)=125 kPa
Volume(V₁)=15·1 L
Temperature (T₁)=25°C=25+273 K=298 K
Similarly, for Oxygen,
Pressure(P₂)= 125 kPa
Volume(V₂)= 44.3 L
Temperature(T₂)=25°C= 298 K
Then, for the mixture,
Volumeof the mixture( V)= 6.25 L
Pressure(P)=?
Temperature (T)= 51°C = 51+273 K=324 K
Then, By Combined gas laws,
or, 
or, 
or, 
∴P=1291.85 kPa
So the total pressure of the mixture in the tank of volume 6.25 litres at 51°C is 1291.85 kPa.
