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Juliette [100K]
3 years ago
8

Write a chemical equation for the dissolution of the AgCl precipitate upon the addition of NH,(aq).

Chemistry
1 answer:
Kobotan [32]3 years ago
7 0

Explanation:

White precipitate of silver chloride get dissolves in excess ammonia to formation of complex between silver ions, chloride ions and ammonia molecules.

The chemical reaction is given as:

AgCl(s)+2NH_3(aq)\rightarrow Ag[(NH_3)_2]^+Cl^-(aq)

When 1 mole of silver chloride is added to 2 mole of an aqueous ammonia it form coordination complex of diaaminesilver(I) chloride.

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Is electricity an essential property of matter ?
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Answer: I think so.. (sorry if i am wrong)

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3 years ago
in the reaction, 2h2 o2 --> 2h2o, how many hydrogen molecules are needed to produce two water molecules?a. 1b. 2c. 3d. 4
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The balanced reaction between Hydrogen and Oxygen to form Water:

 2H₂ + O₂  →  2H₂O

From the equation it already states that:

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Option B.
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3 years ago
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Nadusha1986 [10]

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Charles's law describes the relationship of the volume and temperature of
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3 years ago
Will a precipitate (ppt) form when 20.0 mL of 1.1 × 10 –3 M Ba(NO 3) 2 are added to 80.0 mL of 8.4 × 10 –4 M Na 2CO 3?
erastova [34]

Answer:

A precipitate will form, BaCO₃

Explanation:

When Ba²⁺ and CO₃²⁻ ions are in an aqueous media, BaCO₃(s), a precipitate, is produced following its Ksp expression:

Ksp = 5.1x10⁻⁹ = [Ba²⁺] [CO₃²⁻]

<em>Where the concentrations of the ions are the concentrations in equilibrium</em>

<em />

For actual concentrations of a solution, you can define Q, <em>reaction quotient, </em>as:

Q = [Ba²⁺] [CO₃²⁻]

<em>If Q > Ksp, the ions will react producing BaCO₃, if not, no precipitate will form</em>.

Actual concentrations of Ba²⁺ and CO₃²⁻ are:

[Ba²⁺] = [Ba(NO₃)₂] = 1.1x10⁻³ × (20.0mL / 100.0mL) = 2.2x10⁻⁴M

[CO₃²⁻] = [Na₂CO₃] = 8.4x10⁻⁴ × (80.0mL / 100.0mL) = 6.72x10⁻⁴M

<em>100.0mL is the volume of the mixture of the solutions</em>

<em />

Replacing in Q expression:

Q = [Ba²⁺] [CO₃²⁻]

Q = [2.2x10⁻⁴M] [6.72x10⁻⁴M]

Q = 1.5x10⁻⁷

As Q > Ksp

<h3>A precipitate will form, BaCO₃</h3>

<em />

8 0
3 years ago
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