Answer: 1. HYDROCARBONS? 2. ALKANES?
i'm not exactly AMAZING at this but i did some research and this is what i think it is i'm also not in this grade but i tried.
Since the half-reaction is occurring in a basic solution, add 32OH− to each side of the equation to eliminate the H+ ions.
P₄ +16H₂O + 32OH⁻ ⟶ 4PO₃⁻⁴ + 32H⁺ +32OH⁻
Final reaction :
P₄ + 32OH⁻ ⟶ 4PO₃⁻⁴ + 16H₂O + 20e⁻
A half reaction is either the oxidation or reduction reaction component of a redox reaction. A half reaction is obtained by considering the change in oxidation states of individual substances involved in the redox reaction.
The concept of half-reactions is used to describe what occurs in an electrochemical cell, such as a Galvanic cell battery. Half-reactions can be written to describe both the metal undergoing oxidation (known as the anode) and the metal undergoing reduction (known as the cathode).
Half-reactions are often used as a method of balancing redox reactions. For oxidation-reduction reactions in acidic conditions, after balancing the atoms and oxidation numbers, one will need to add H+ ions to balance the hydrogen ions in the half reaction.
For oxidation-reduction reactions in basic conditions, after balancing the atoms and oxidation numbers, first treat it as an acidic solution and then add OH- ions to balance the H+ ions in the half reactions (which would give H2O).
Learn more about Half reactions here : brainly.com/question/2491738
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Answer:
A. 145.2 g NH3
B. 0.76 g H2
C. 1.41 x 10^22 molecules NH3
Explanation:
A. 1 mol N2 -> 2 mol NH3
4.27 mol N2 -> x
x= (4.27 mol N2 * 2 mol NH3)/1 mol N2 x= 8.54 mol NH3
1 mol N2 -> 17 g
8.54 mol N2 -> x x= 145.2 g NH3
B.
2 g H2 -> 34 g NH3
x -> 13.01 g NH3
x= 0.76 g H2
C.
2 g H2 -> 34 g NH3
0.0235 g H2 -> x
x= 0.39 g NH3
0.39 g NH3 (1 mol NH3/17 g NH3)(6.023 x 10^23 molecules/1 mol NH3) =
1.41 x 10^22 molecules NH3
The answer is ice. Nice brain teaser!
