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3 years ago

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Which of the following happens during cell division? (A) Energy is created (B) Waste is eliminated (C) Carbon dioxide is release

d (D) Damaged cells are replaced

2 answers:

bogdanovich [222]3 years ago

7 0

D-Damaged cells are replaced

Temka [501]3 years ago

6 0

Answer:

D Have a good day!

Explanation:

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What is the percentage yield of O2 if 12.3 g of KClO3 (molar mass 123 g) is decomposed to produce 3.2 g of O2 (molar mass 32 g)

My name is Ann [436]

Answer:

The percentage yield of O2 is 66.7%

Explanation:

Reaction for decomposition of potassium chlorate is:

2KClO₃ → 2KCl + 3O₂

The products are potassium chloride and oxygen.

Let's find out the moles of chlorate.

Mass / Molar mass = Moles

12.3 g / 123 g/mol = 0.1 mol

So ratio is 2:3, 2 moles of chlorate produce 3 mol of oxygen.

Then, 0.1 mol of chlorate may produce (0.1 .3)/ 2 = 0.15 moles

Let's convert the moles of produced oxygen, as to find out the theoretical yield.

0.15 mol . 32 g/ 1mol = 4.8 g

To calculate the percentage yield, the formula is

(Produced Yield / Theoretical yield) . 100 =

(3.2g / 4.8g) . 100 = 66.7 %

8 0

3 years ago

Nuclei may be unstable if they have

weqwewe [10]

Nuclei may be unstable if they have
a too much energy.
b too many protons.
C an unstable ratio of protons to neutrons.
d any of the above.

The answer would be, D any of the above.
Hope this helps

3 0

3 years ago

PLEASE HELP ASAP !!!!!!!!!!!!!!!!!!!!!!!!!!!!!

In-s [12.5K]

+2, because the element has more protons than electrons now

5 0

3 years ago

PLEASE HELP AND EXPLAIN!Calculate the energy required to heat 187.0 g of ammonia from 36.1 °C to 52.9 °C. Assume the specific he

Alenkinab [10]

Answer:

$E=1.48x10^4J$

Explanation:

Hello!

In this case, since the energy implied in a heating process is computed by using the following equation:

$E=mC(T_f-T_i)$

Whereas m is the mass, C the specific heat and T the temperature. In such a way, by plugging in the given mass, specific heat and temperatures, we obtain the following energy:

$E=187.0g*4.703\frac{J}{g\°C} (52.9\°C-36.1\°C)\\\\E=1.48x10^4J$

Considering that the specific heat can by used by unit of °C or K because their difference is equivalent.

Regards!

3 0

3 years ago

For the reaction, calculate how many grams of the product form when 14.4 g of Br2 completely reacts. Assume that there is more t

lora16 [44]

Answer:

The answer to your question is 21.45 g of KBr

Explanation:

Chemical reaction

2K + Br₂ ⇒ 2KBr

14.4 ?

Process

1.- Calculate the molecular mass of bromine and potassium bromide

Bromine = 2 x 79.9 = 159.8g

Potassium bromide = 2(79.9 + 39.1) = 238 g

2.- Solve it using proportions

159.8 g of Bromine ------------ 238 g of potassium bromide

14.4 g of Bromine ------------ x

x = (14.4 x 238) / 159.8

x = 3427.2 / 159.8

x = 21.45g of KBr

7 0

3 years ago