We have to find the lengths of the diagonals KM and JL:
d ( KM ) = √ (( - a - b )² + ( 0 - c )²) = √ (( a + b )² + c² )
d ( JL ) = √ ( ( a - ( - b ) )² + ( 0 - c )²) = √ ( ( a + b )² + c² )
So the lengths of the diagonals KM and JL are congruent.
The lengths of the diagonals of the isosceles trapezoid are congruent.
Answer:
2 bc cos A
Step-by-step explanation:
Cosine rule
The answer
the complement of the question is
What is the value of y?
2
5
7
<span>8
</span>
According to the image, HKJ and FGH are similar, we can apply the theorem of thales
since GK and GF are parallels, so
HK / HF = HJ / HG = KJ / GF and as we see on the figure, HK = HF /2, this implies 2HK =HF
HK / 2HK = KJ / GF it is equivalent to 1/2 = 2y+5 / 5y +3
likewise, equivalent to 5y +3 = 4y +10, 5y-4y = 10-3, and y = 7
so the answer is 7
Answer:
Rhombus
Step-by-step explanation:
It does not have congruent diagonals
