The magnitude of the average net force acting on the truck during the 21.0 s interval is about 626 N
<h3>Further explanation</h3>
Acceleration is rate of change of velocity.
<em>a = acceleration ( m/s² )</em>
<em>v = final velocity ( m/s )</em>
<em>u = initial velocity ( m/s )</em>
<em>t = time taken ( s )</em>
<em>d = distance ( m )</em>
Let us now tackle the problem!
<u>Given:</u>
mass of truck = m = 2150 kg
initial speed of truck = u = 55.0 km/h = 15⁵/₁₈ m/s
final speed of truck = v = 33.0 km/h = 9¹/₆ m/s
time taken = t = 21.0 s
<u>Asked:</u>
average net force = ∑F = ?
<u>Solution:</u>
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Kinematics