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Arte-miy333 [17]
4 years ago
13

Why does a rock not visibly vibrate?

Physics
1 answer:
eimsori [14]4 years ago
8 0
Because it is really hard and rocks can't be visible or vibrate
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What type of sound is produced when string vibrates rapidly?
amid [387]
The faster a string vibrates, the higher frequency sound it produces,
and the higher the pitch is that we hear. 
8 0
3 years ago
As a bicycle pump inflates a tyre, it pressure rises from 30 kPa to 40 kPa at constant temperature of 30 °C. By assuming the air
MArishka [77]

This question involves the concepts of work done, pressure, and temperature.

The work done per mol of the air is "-724.71 J/mol".

Using the given formula for work done:

W=RTln\frac{P_1}{P_2}

where,

W = work done per mol = ?

R = universal gas constant = 8.314 J/mol.k

T = absolute temperature = 30°C + 273 = 303 k

P₁ = initial pressure = 30 KPa

P₂ = final pressure = 40 KPa

Therefore,

W= (8.314\ J/mol.k)(303\ k)ln\frac{30\ KPa}{40\ KPa}\\

<u>W = -724.71 J/mol</u>

<u></u>

Learn more about pressure here:

brainly.com/question/23358029?referrer=searchResults

7 0
3 years ago
A motor-driven winch pulls a 50.0 kg student 5.00 m up the rope at a constant speed of 1.25 m/s. how much power does the motor u
nadya68 [22]
Power is the rate work done given by dividing work done by unit time. It is measured in watts equivalent to J/s.
In this case the force by the student is mg = 490 N (taking g as 9.8m/s²)
Work done is given by force × distance,
Therefore, Power =(force × distance)/ time, but velocity/speed =distance/time
Thus, Power = force × speed/velocity
                     = 490 N × 1.25
                     = 612.5 J/S (Watts)
Hence, power will be 612.5 Watts.
7 0
4 years ago
A heat engine accepts 200,000 Btu of heat from a source at 1500 R and rejects 100,000 Btu of heat to a sink at 600 R. Calculate
diamong [38]

To solve the problem it is necessary to apply the concepts related to the conservation of energy through the heat transferred and the work done, as well as through the calculation of entropy due to heat and temperatra.

By definition we know that the change in entropy is given by

\Delta S = \frac{Q}{T}

Where,

Q = Heat transfer

T = Temperature

On the other hand we know that by conserving energy the work done in a system is equal to the change in heat transferred, that is

W = Q_{source}-Q_{sink}

According to the data given we have to,

Q_{source} = 200000Btu

T_{source} = 1500R

Q_{sink} = 100000Btu

T_{sink} = 600R

PART A) The total change in entropy, would be given by the changes that exist in the source and sink, that is

\Delta S_{sink} = \frac{Q_{sink}}{T_{sink}}

\Delta S_{sink} = \frac{100000}{600}

\Delta S_{sink} = 166.67Btu/R

On the other hand,

\Delta S_{source} = \frac{Q_{source}}{T_{source}}

\Delta S_{source} = \frac{-200000}{1500}

\Delta S_{source} = -133.33Btu/R

The total change of entropy would be,

S = \Delta S_{source}+\Delta S_{sink}

S = -133.33+166.67

S = 33.34Btu/R

Since S\neq   0 the heat engine is not reversible.

PART B)

Work done by heat engine is given by

W=Q_{source}-Q_{sink}

W = 200000-100000

W = 100000 Btu

Therefore the work in the system is 100000Btu

4 0
3 years ago
Name five uses of electromagnetic radiation ​
klio [65]

Answer:

Behaviour and uses of electromagnetic waves

Radio waves. Radio waves are used for communication such as television and radio. ...

Microwaves. Microwaves are used for cooking food and for satellite communications. ...

Infrared. ...

Visible light. ...

Ultraviolet radiation.

8 0
3 years ago
Read 2 more answers
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