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Usimov [2.4K]
3 years ago
11

A pure-bred normal tail, dark skin, smooth skin mouse is crossed to a pure-bred mouse that is tail-less, pale skin, and rough sk

in. What are the gamete genotypes produced by each of these mice?
Biology
1 answer:
Ivanshal [37]3 years ago
5 0

Answer:

TTppRR will produce TpR gametes.  ttPPrr  will produce tPr gametes.

Explanation:

Let us assume:

Normal tail : T, Tail less : t, Pale skin : P, Dark skin : p, Smooth skin : R, Rough skin : r

A pure-bred normal tail, dark skin, smooth skin mouse and a pure-bred mouse that is tail-less, pale skin, and rough skin  crossed together then,

TTppRR x ttPPrr

One allele from every gene comes in a gamete thus, TTppRR will produce TpR gametes.  ttPPrr  will produce tPr gametes.

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If liz exhibited symptoms of impaired work performance, general fatigue, pale skin, depressed immune function, impaired cognitiv
satela [25.4K]

Answer;

-iron-deficiency anemia.

Liz is likely to be suffering from iron-deficiency anemia.

Explanation;

- Iron deficiency anemia develops when body stores of iron drop too low to support normal red blood cell (RBC) production. It may be caused by the Inadequate dietary iron, impaired iron absorption, bleeding, or loss of body iron in the urine.

4 0
2 years ago
What is the natural nutrient enrichment of a shallow lake, estuary, or slow moving stream called? A .oligotrophy
kaheart [24]

Answer:

Eutrophication

Explanation:

Eutrophication is the name given to the natural nutrient enrichment of a shallow lake, estuary, or slow-moving stream. It is caused mostly by runoff of plant nutrients, such as nitrates and phosphates, from surrounding land.

3 0
3 years ago
1. 7. The ability to taste the chemical PTC is determined by a single gene in humans with the ability to taste given by the domi
Komok [63]

Answer:

3/4 taster; 1/4 non-taster

The likelihood that their first child will be a taster: 75 %

Explanation:

Complete dominance occurs when a dominant gene variant or 'allele' completely masks the expression of the recessive allele in heterozygous individuals (i.e., individuals carrying one copy of the dominant allele and one copy of the recessive allele). In this case, both parents are heterozygous for a single gene trait (i.e., the ability to taste) which is ruled by complete dominance. In consequence, the expected phenotypic ratio in the progeny (F1) will be:  

- Alleles: T (dominant taster allele); t (recessive non-taster allele)

- Parental cross: Tt x Tt

- Punnett Square from this cross:

         T        t

T       TT     Tt

t        Tt       tt

Expected F1 phenotypic ratio: 3/4 taster (i.e., 1/4 TT genotype + 1/2 genotype Tt = 3/4 or 75%); 1/4 non-taster (tt genotype = 1/4 or 25%). Moroever, the chance that the first child has the taster phenotype is 3/4 (75%).

3 0
2 years ago
What kind of organisms perform photosynthesis?
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Green plants which contain chloroplast perform photosynthesis
4 0
3 years ago
Read 2 more answers
Also located on the X chromosome of a cat is a gene that codes for deafness. This gene is recessive. A black female cat that is
anyanavicka [17]

Answer:

Explanation:

This gene is an X linked recessive trait, thus for it to be expressed in the females, it has to be in the homozygous recessive form (both X chromosomes will carry this trait dd). For males, only one copy which is in the recessive condition is needed for it to be expressed. Thus, a cross between

female           male

XDXd     x      XDY

                     XD             Y

XD              XDXD        XDY

Xd              XDXd         XdY

the offspring phenotype: normal females: 1/2

                                         normal male: 1/4

                                         deaf male: 1/4

5 0
3 years ago
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