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irga5000 [103]
3 years ago
7

Given the function, f(x) = | x-2 | + 1

Mathematics
1 answer:
Genrish500 [490]3 years ago
8 0
What do you need to do with this?
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A student is writing a research paper and must include sources from both magazines and books.
SIZIF [17.4K]
B 100% is right answer
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3 years ago
Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v
k0ka [10]

I'll use subscript notation for brevity, i.e. \frac{\partial f}{\partial x}=f_x.

By the chain rule,

z_u=z_xx_u+z_yy_u

z_v=z_xx_v+z_yy_v

z_w=z_xx_w+z_yy_w

We have

z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}

and

\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}

When u=1,v=1,w=0, we have

\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}

and the partial derivatives take on values of

\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}

So we end up with

\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}

3 0
3 years ago
I NEED HELP PLEASE PLEASE
Svetlanka [38]

9514 1404 393

Answer:

  y = 12

Step-by-step explanation:

Triangles ABD and CBD are congruent, so DA = DC:

  3y +6 = 5y -18

  24 = 2y . . . . . . . . add 18-3y; next, divide by 2

  12 = y

_____

<em>Additional comment</em>

In some variations of this question, you may be asked to solve for x. Since the angles are equal, you have ...

  3x -1 = 34 -2x  ⇒  5x = 35  ⇒  x = 7 . . . (consistent with ∠ABC = 40°)

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3 years ago
Which variable did you plot on the x-axis, and which variable did you plot on the y-axis? Explain why you assigned the variables
Maksim231197 [3]
The height should be on the x axis and arm span on the y axis
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The question is asking me what’s the slope and is giving me 4 options and it’s very difficult
Andreas93 [3]
The answer to your question is C
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Read 2 more answers
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