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Alexxandr [17]
3 years ago
5

I NEED HELP PLEASE!!

Mathematics
1 answer:
ziro4ka [17]3 years ago
7 0
Square root of 12 (\sqrt{12})
Square root of 18 (\sqrt{18})

You can multiply these two together to get:

\sqrt{12 * 18} =  \sqrt{216} = 6 \sqrt{6}

Therefore your answer is 6 square root of 6.
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30 points!<br>please help<br><br>in return brainliest and special thanks
a_sh-v [17]
21. >

22. Distributive Property
5 0
3 years ago
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It is known that 10% of the calculators shipped from a particular factory are defective. In a random sample of ten calculators,
umka2103 [35]

Answer:

0.7361

Step-by-step explanation:

In this question we have

number to be 10

Then we have a probability of 10% = 0.10

We have q = 1-p

= 1-0.10 = 0.90

Then the probability of not more than 1 being defective:

P(x=0) + p(x= 1)

(10C0 x 0.1⁰ x 0.9^10-0)+(10C1 x 0.1¹ x 0.9^10-1)

= 1 x1 x0.3487 + 10 x 0.1 x 0.3874

= 0.3487 + 0.3874

= 0.7361

This is the the required probability and this answers the question.

probability = 10 percent = 0.1

q= 1- 10percent = 90% = 0.9

n = 4

To get the required probabiltiy for this question is

P(not greater than one is defective )=P(x=0)+P(x=1)

= 4C0x(0.1)⁰x(0.9)⁴+4C1x(0.1)¹x(0.9)³

= 0.9477

The required probability is 0.9477

5 0
3 years ago
Which of the following accurately pairs the part of an atom to its charge ?
rusak2 [61]
Electron—negative charge

Happy studying ^_^
8 0
3 years ago
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(Z-6) divided by 3 for z= 15.9
scoray [572]
Simply plug in \sf{z=15.9} into \sf{\frac{z-6}{3}}

So:

\sf{\frac{15.9-6}{3}}

Simplify that more:

\sf{\frac{9.9}{3}}

And that finally becomes 

\sf{3.3}

So when \sf{z=15.9} the answer will be \boxed{\sf{3.3}}
4 0
3 years ago
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There are 4 jacks and 13 clubs in a standard, 52-card deck of playing cards. What is the probability that a card picked at rando
Tju [1.3M]

With 4 jacks in the deck of 52, there is a 4/52 = 1/13 probability of drawing 1 jack.

With 13 clubs in the deck, there is a 13/52 = 1/4 probability of drawing 1 card of clubs.

1 of the cards in the deck is both a jack and of suit of clubs, which has a 1/52 probability of being drawn.

P(club OR jack) = P(club) + P(jack) - P(club AND jack) = 13/52 + 4/52 - 1/52 = 16/52 = 4/13

So the answer is B.

3 0
3 years ago
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