Answer:
Explanation:
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In this case, since the catalytic reactions involve the presence of a catalyst that decrease the activation energy of the undergoing chemical reaction, when we need to include it in the chemical equation, we usually put on or underneath the reaction arrow, just as shown below:
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I'm pretty sure that is true. not 100% sure but hope this is right. sorry if wrong!
To find this you have to find the molar mass of CO2 which you can get on the periodic table, 12 + 16 + 16 = 44 g/mol
4.49 x 10^0 / 44 g/mol = .1020 mol CO2
1 mol = 6.022 x 10^23 molecules (avogadros number)
so .1020 mol x 6.022 x 10^23 =
6.14 x 10 ^22 molecules CO2
Start with 2.95 g of aspartame. Find g per mole of aspartame. Then find moles of nitrogen. 2 N to 1 aspartame. Then there are 14.00067 g of N per 1 mole. Change g to milligrams with the 10^-3 g
Answer:
[COCl₂] = 0.373 mol·L⁻¹
[CO] = [Cl₂] = 0.069 mol·L⁻¹
Explanation:
The balanced equation is
CO + Cl₂ ⇌ COCl₂
Data:
Kc = 77.5
n(CO₂) = 0.442 mol
n(Cl₂) = 0.442 mol
V = 1.00 L
1. Calculate the initial concentration of CO and Cl₂
Step 2. Set up an ICE table.
Step 3. Calculate the equilibrium concentrations
[COCl₂] = x mol·L⁻¹ = 0.373 mol·L⁻¹
[CO] = [Cl₂] = (0.442 - 0.373) mol·L⁻¹ = 0.069 mol·L⁻¹