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lisabon 2012 [21]
3 years ago
11

Is this equation right? ​

Chemistry
2 answers:
m_a_m_a [10]3 years ago
8 0

Answer:

no

Explanation:

because the characters are invalid

loris [4]3 years ago
4 0

Answer:

no

Explanation:

because they are not valid

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3 0
3 years ago
How is an average mass different from a weighted mass
romanna [79]

In an average mass, each entry has equal weight. In a weighted average, we multiply each entry by a number representing its relative importance.

Assume that your class consists of 15 girls and 5 boys. Each girl has a mass of 54 kg, and each boy has a mass of 62 kg.

<em>Average mass</em> = (girl + boy)/2 = (54 kg + 62 kg)/2 = <em>58 kg</em>

<em>Weighted average (Method 1) </em>

Use the <em>numbers of each</em> gender (15 girls + 5 boys) ,

Weighted average = (15×54 kg + 5×62 kg)/20 = (810 kg + 310 kg)/20

= 1120 kg/20 = <em>56 kg</em>.

If you put all the students on one giant balance, their total mass would be

1120 kg and the average mass of a student would be <em>56 kg. </em>

<em>Weighted average (Method 2) </em>

Use the <em>relative percentages</em> of each gender (75 % girls and 25 % boys).

Weighted average = 0.75×54 kg + 0.25×62 kg = 40.5 kg + 15.5 kg = <em>56 kg</em>

Each girl contributes 40.5 kg and each boy contributes 15.5 kg to the <em>weighted average</em> mass of a student.

6 0
3 years ago
Will give brainlist need answers asap
Serga [27]

Answer:

40 g

Explanation:

Find the line labeled KClO3 (which might take you a min, theres a lot of lines here)

Notice that when the line creates a direct point, you can measure the exact temperature needed to dissolve a certain amount (like how they gave 30 degrees and it lined up perfectly with the 10 g line. )

Since its asking for the amount at 80 degrees, all you need to do is trace the line to the 80 degree point, and look at the grams. (notice it made a direct point, so there definitely should be any decimals or guesswork)

By reading the graph, you can tell that at 80 degrees, it dissolves 40 grams, and that is your answer.

Hope this helps :)

3 0
3 years ago
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