Answer:
a. $70
b. $(40 + 10x)
Step-by-step explanation:
The standard cost of the charges is $40 per month but an extra $10 per GB over the included amount.
a. Firstly the cost for a month in which he uses 3GB over the limit
we have a standard of $40, then he has to pay $10 per GB for the 3GB over the limit.
Thus the cost of the 3GB is $10 * 3 = $30
The total cost for using 3GB above the limit would be $40 + $30 = $70
b. For using x GB above the limit
He has to pay $10 per each GB above the limit
Thus, the amount to be paid for x GB above the limit would be x * $10 = $10x
So the total amount to be paid would be the base fee plus over the limit fee= $(40 + 10x)
Answer:
22
Step-by-step explanation:
Answer:
14
Step-by-step explanation:
Given the indicinal expression 64^5/6 + 27^2/3 - 81^3/4
According to indices;
![a^{m/n} = (\sqrt[n]{a}) ^m](https://tex.z-dn.net/?f=a%5E%7Bm%2Fn%7D%20%3D%20%28%5Csqrt%5Bn%5D%7Ba%7D%29%20%5Em)
Applying this to the question
![64^{5/6} \\= (\sqrt[6]{64}) ^5\\= 2^5= 32](https://tex.z-dn.net/?f=64%5E%7B5%2F6%7D%20%5C%5C%3D%20%28%5Csqrt%5B6%5D%7B64%7D%29%20%5E5%5C%5C%3D%202%5E5%3D%2032)
Similarly
![27^{2/3}\\= (\sqrt[3]{27}) ^2\\= 3^2\\= 9\\](https://tex.z-dn.net/?f=27%5E%7B2%2F3%7D%5C%5C%3D%20%28%5Csqrt%5B3%5D%7B27%7D%29%20%5E2%5C%5C%3D%203%5E2%5C%5C%3D%209%5C%5C)
Also;
![81^{3/4}\\= (\sqrt[4]{81}) ^3\\= 3^3\\= 27](https://tex.z-dn.net/?f=81%5E%7B3%2F4%7D%5C%5C%3D%20%28%5Csqrt%5B4%5D%7B81%7D%29%20%5E3%5C%5C%3D%203%5E3%5C%5C%3D%2027)
Substitute inti the original equation
64^5/6 + 27^2/3 - 81^3/4
= 32 + 9- 27
= 41 - 27
= 14
Hence the required answer is 14
Answer:5-]2u0972=071-984622324rt1yuiouytrewqwertyuiop[]
Step-by-step explanation:
Answer:
Anchorage
Barrow
Juneau
are the top 3 records low... And for the rest, i'm too lazy. Good luck finding someone, though! And try looking it up, and doing some research, maybe?
Step-by-step explanation:
