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galben [10]
3 years ago
12

Which logarithmic equation is equivalent to 82 = 64?

Mathematics
1 answer:
Alex777 [14]3 years ago
5 0
8^2 = 64 \\ \log_{8}{64}=2
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What is x given angle ABC~ angle DBE~ ?
Dovator [93]

30:50 = 3:5

x : x+25 = 3:5

25/2 x 3 = 37.5

6 0
3 years ago
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HELP ASAP WILL GIVE BRAINLIEST!! What is the value of 8.25p + 3.99c, when p=12 and c=8.
DENIUS [597]

Answer:

130.92

Step-by-step explanation:

8.25(12)+3.99(8)

99+31.92

130.92

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3 years ago
.<br> 1.<br> f(x) = -2lx- 3| +1<br><br> How do I graph this?
ira [324]

Answer:

See explanation

Step-by-step explanation:

f(x) = -2lx-3| +1

1.lx-3|==>Translate the basic absolute value graph f(x)=|x| 3 units to the right

2. -lx-3| ==> Flip the graph over the x-axis

3. -2lx-3| ==> Double all the y-coordinates of the graph

4. -2lx-3| +1 ==> Translate the graph 1 unit up

4 0
2 years ago
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h(t)=(t+3) 2 +5 h, left parenthesis, t, right parenthesis, equals, left parenthesis, t, plus, 3, right parenthesis, squared, plu
lesya692 [45]

Answer:

1

Step-by-step explanation:

If I understand the question right, G(t) = -((t-1)^2) + 5 and we want to solve for the average rate of change over the interval −4 ≤ t ≤ 5.

A function for the rate of change of G(t) is given by G'(t).

G'(t) = d/dt(-((t-1)^2) + 5). We solve this by using the chain rule.

d/dt(-((t-1)^2) + 5) = d/dt(-((t-1)^2)) + d/dt(5) = -2(t-1)*d/dt(t-`1) + 0 = (-2t + 2)*1 = -2t + 2

G'(t) = -2t + 2

This is a linear equation, and the average value of a linear equation f(x) over a range can be found by (f(min) + f(max))/2.

So the average value of G'(t) over −4 ≤ t ≤ 5 is given by ((-2(-4) + 2) + (-2(5) + 2))/2 = ((8 + 2) + (-10 + 2))/2 = (10 - 8)/2 = 2/2 = 1

Click to let others know, how helpful is it

3 0
3 years ago
What is the domain of the set (-3,5), (2,0), (7,-5)​
Valentin [98]

The domain is all x-values.

The domain is -3, 2, 7

The range is all y-values

The range is 5, 0, -5

Best of Luck!

4 0
3 years ago
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