If <em>x</em> = -1, you have
2(-1) + 3 cos(-1) + <em>e</em> ⁻¹ ≈ -0.0112136 < 0
and if <em>x</em> = 0, you have
2(0) + 3 cos(0) + <em>e</em> ⁰ = 4 > 0
The function <em>f(x)</em> = 2<em>x</em> + 3 cos(<em>x</em>) + <em>eˣ</em> is continuous over the real numbers, so the intermediate value theorem applies, and it says that there is some -1 < <em>c</em> < 0 such that <em>f(c)</em> = 0.
Answer:
-18
Remember PEMDAS.
Step-by-step explanation:
Answer:
substitute the input (the given number or expression) for the function's variable (place holder, x).
Replace the x with the number or expression.
Example:
f(x)=3x-5 and f(4)
f(x)=3(4)-5
f(x)=12-5
f(x)=7
final answer is (4,7)
Answer:
ir
Step-by-step explanation:
irregular
regular
what do you notice different?
the both have r, e, g, u, l, a, r, but one has ir at the beginning.
Answer:
7^12
Step-by-step explanation:
We know that a^b ÷ a^c = a^(b-c)
7 ^ 14÷ 7^2
7^ (14-2)
7^12
