Answer:
A. VG = 80
B. Broad sense heritability = 0.80
C. Narrow sense heritability = 0.30
D. Average yield = 430 Units
Explanation:
A. Given that
VA = 30
VD = 50
VI = assumed not available
Therefore
Total genetic variance (VG) = VA + VD
= 30 + 50
= 80
VG = 80
B. Given that
VP = 100
VG = 80
Broad sense heritability, H2 = VG/VP
= 80/100
= 0.80
C. Given that
VA = 30
VP = 100
Narrow sense heritability, h2 = VA/VP
=30/100
= 0.30
D. The difference in selection = 500 - 400
= 100
Recall,
Selection response is heritability multiplied by selection differential.
That is
R = h2S
Selection differential = 100
Heritability h2 = 0.30
Selection response = 0.30 × 100
= 30units
Therefore, expected average yield = 400 + 30
= 430 Units
Answer:
Deleterious alleles appear sporadically in a population
Explanation:
A population with a deleterious allele will have no or few individuals that have the ability to pass along these traits. These alleles appear less in a population because of selective pressure but they are not always absent. The alleles appear less often but are are not always passed on and the others that are genetically fit are able to pass along their genes. The reason the population equilibrium is not zero is because these alleles do appear but they are not necessarily passed along. These individuals may not be able to reproduce or reach the age of reproduction.
Deleterious alleles appear more often, making individuals less fit genetically, i.e. they pass fewer copies of their genes to future generations. Put another way, natural selection purges the deleterious alleles.
Answer:
Tropical Zone
Explanation: Its near the equator with warm air masses with the average temperature in the coldest month is 18 °C. This is warmer than the average temperature of the warmest month in the polar zone.
The answer is Closed. Hope it helps
Answer:
A. Carotene
Explanation:
It is an orange/red pigment which is seen during the fall.
