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Ray Of Light [21]
3 years ago
6

Kerry drew a number line starting at 0, point a, and ending at 1, point c. Halfway between points a and c, kerry added point b.

Which statement is true about the number line? A) the distance between points a and c is halfway between points a and b. B) the distance between points a and b is equal to the distance between points b and c. C)without using a ruler to measure, no true statements can be made about the number line. D)the distance between points a and b is not equal to the distance between points b and c.
Mathematics
1 answer:
Sholpan [36]3 years ago
7 0

Answer: B) is the right answer→the distance between points a and b is equal to the distance between points b and c.


Step-by-step explanation:

As Kerry drew a number line starting at 0, point a, and ending at 1, point c and halfway between points a and c, he added point b.

.⇒ab=1/2 of ac and bc= 1/2 of ac or b is the mid point of line segment ac.

⇒ ab=bc(∵things which are equal to the same thing are equal to one another....→Euclid's first postulate)

Therefore, option B) the distance between points a and b is equal to the distance between points b and c is correct.

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We gave a national verbal proficiency test that has a mean score of 500 with a standard deviation of 75. What raw score would co
charle [14.2K]

Answer:

519

Step-by-step explanation:

Let's assume that the scores for the national verbal proficiency test follow a normal distribution.

Mean score (μ) = 500

Standard deviation (σ) = 75

According to a Z-score table, the score for the 60th percentile is roughly z = 0.253

For any score "x", the z-score is given by:

Z=\frac{X-\mu}{\sigma}

For z = 2.53:

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4 0
4 years ago
What is the distance between (-1,4) and (2,0)
Ivahew [28]

Answer: 5

The Distance between the coordinates of two points is measured by distance formula.

Step-by-step explanation:

The Distance between the coordinates of two points P(x1,y1) and Q(x2,y2) is measured by

Distance PQ= \sqrt{}(x2-x1)²+(y2-y1)²

So, the distance between (-1,4 ) and (2,0) can be calculated by

Distance= \sqrt{}(2-(-1))²+(0-4)²

              = \sqrt{}(3)²+(-4)²

              =\sqrt{}9+16 = \sqrt{}25                                                  as    \sqrt{}25 = 5

Distance = 5

So the distance between the two coordinates is 5.

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3 years ago
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