Kerry drew a number line starting at 0, point a, and ending at 1, point c. Halfway between points a and c, kerry added point b.
1 answer:
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Answer:
{ 0, 3, - 3 }
Step-by-step explanation:
f(x) = x(2x - 3)(x + 3)
to find the zeros let f(x) = 0 , that is
x(2x - 3)(x + 3) = 0
equate each factor to zero and solve for x
x = 0
2x - 3 = 0 ⇒ 2x = 3 ⇒ x =
x + 3 = 0 ⇒ x = - 3
zeros are { 0, , - 3 }
The ball will hit the ground at 2 seconds.
Step-by-step explanation:
Given that,
The path of the ball = h(x)=−2x2+1x+6
Here,
x is the time while h is the height of ball.
When the ball will hit the ground, the height will become zero. Therefore,
h(x)=−2x2+1x+6
0 =−2x2+1x+6
or
2x2 -1x - 6 = 0
This is a quadratic equation, hence by applying quadratic equation formula:
here,
a = 2
b = -1
c = -6
Putting these values in formula, we get
x = 2, -3/2
As the time cannot be negative. Therefore, the ball will hit the ground at 2 seconds.