3 years ago

Find the co-ordinates of the foot of the perpendicular drawn from the point (6, 3) to the line by

Mathematics

1 answer:

spin [16.1K]3 years ago

6 0

Answer:

(6.4, 2.2)

Step-by-step explanation:

(3-1)/(8-4) = 2/4 = 1/2 = m

y = mx + b

1 = 1/2(4) + b

-1 = b

y = 1/2x - 1

perpendicular slope is -2

y = mx + b

3 = -2(6) + b

15 = b

y = -2x + 15

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An isosceles triangle has base angles that each measure 48°. Which equation can be used to find x, the measure of the third angl

Colt1911 [192]

Answer:

180-48/2

Step-by-step explanation:

180-48=

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2 years ago

The height of a triangle is 3cm less than twice the base. The area is 10cm2

Kamila [148]

Answer:

The base is 4cm and the height is 5cm.

Step-by-step explanation:

This is a solve the system question. Call H the height of the triangle and B the base. The question tells us:

$H=2B-3$

and

$\frac{B \times H}{2}=10$

Sub the first equation into the second (as H is already isolated). You will end up with a quadratic equation - solve that any way you wish (e.g. quadratic formula). I've provided the factored form below which shows you the roots:

$\frac{B(2B-3)}{2}=10\\\frac{2B^2-3B}{2}=10\\2B^2-3B=20\\2B^2-3B-20=0\\(2B+5)(B-4)=0\\B= - \frac{5}{2},4$

In this question, we take B=4. You can't have a negative side length so the other answer is eliminated. Now sub the value for B into either of the original equations. I'll use the first, again because H is already isolated:

$H=2(4)-3\\H=8-3\\H=5$