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Rufina [12.5K]
3 years ago
11

ASAP PLS HELP What is chemical potential energy?

Physics
1 answer:
mash [69]3 years ago
5 0

Answer:

chemical potential of a species is energy that can be absorbed or released due to a change of the particle number of the given species, e.g. in a chemical reaction or phase transition.

Explanation:

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What is air temperature meausered with?
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Temperature is usually expressed in degrees Fahrenheit or Celsius. 0 degrees Celsius is equal to 32 degrees Fahrenheit. Room temperature is typically considered 25 degrees Celsius, which is equal to 77 degrees Fahrenheit.

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How is it possible for one electrically neutral atom to exert an electrostatic force on other electrically neutral atom?
Free_Kalibri [48]

Answer:

Explained

Explanation:

Although Atom are electrically neutral. But atom atom is combination of nucleus and electrons. The nucleus of the atom is composed neutron and positively charged protons. On the outside of nucleus at some distance are the electrons which are negatively charged. So, there is difference in position of the two differently charge species. So, this way a electrically neutral atom can exert a electrostatic force on other electrically neutral atom

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Which is NOT a property of an acid
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A 35 grams bullet travels with a velocity of magnitude 126 km/h. What is the bullet's linear momentum?
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3 0
3 years ago
Tungsten has a temperature coefficient of resistivity of 0.0045 (c°)-1. a tungsten wire is connected to a source of constant vol
Murljashka [212]

Answer:

131.1^{\circ}C

Explanation:

The power delivered in the wire is given by:

P=\frac{V^2}{R}

where V is the voltage of the battery and R is the resistance of the wire.

Since the voltage of the battery is constant, we can rewrite this equation as follows:

V^2 = PR=const. (1)

At the beginning, the initial resistance is R_0, and the power delivered is P_0. Later, when the temperature increases, the power becomes P_1 = \frac{2}{3}P_0, and the new resistance is R_1. Using (1), we can write

P_0 R_0 = \frac{2}{3}P_0 R_1\\R_1 = \frac{3}{2}\frac{P_0 R_0}{P_0}=\frac{3}{2}R_0 (2)

So, the new resistance must be 3/2 of the initial resistance.

We know that the resistance increases linearly with the temperature, as

R_1 = R_0 (1+\alpha \Delta T)

where

\alpha = 0.0045 ^{\circ}C^{-1} is the temperature coefficient

\Delta T is the change in temperature

Using (2), we can rewrite this equation as

\frac{3}{2}R_0 = R_0(1+ \alpha \Delta T)

and we find:

\frac{3}{2}=1+\alpha \Delta T\\\Delta T=\frac{\frac{3}{2}-1}{\alpha}=111.1 ^{\circ}

So, the new temperature of the wire must be

T_f = 21^{\circ}+111.1^{\circ}=132.1^{\circ}

6 0
4 years ago
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