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sukhopar [10]
3 years ago
9

Which atom is being researched as a possible ingredient of magnetic soap

Physics
1 answer:
maxonik [38]3 years ago
3 0

Answer:

iron

Explanation:

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A 5-kg ball collides inelastically head-on with a 10-kg ball, which is initially stationary. Which of the following statements i
NARA [144]

Answer:

The magnitude of the change of velocity the 5-kg ball experiences is less than that of the 10-kg ball.

Explanation:

In inelastic collision, the total momentum is always conserved after collision but the kinetic energy is reduced.

Momentum is Mass X velocity.

5 kg ball is in motion, while 10 kg ball is stationary; that is zero velocity.

The momentum of 10 kg ball before collision is zero while the momentum of 5 kg ball before collision is more than zero. Therefore, the magnitude of change in momentum will not be equal.

Next possible options are in kinetic Energy

Initial Kinetic energy = \frac{1}{2}mu^2

Final kinetic energy =\frac{1}{2}mv^2

Change in kinetic energy = Final Kinetic Energy - Initial Kinetic Energy

Change in kinetic energy of 5kg ball = \frac{1}{2}mv^2 -\frac{1}{2}mu^2 = \frac{1}{2}m(v-u)^2

Since the 5-kg ball has initial velocity (u), the magnitude of the change in velocity will be reduced.

Change in kinetic energy of 10kg ball:

the ball is initially at rest, therefore the initial velocity (u) will be zero (0)

Δ K.E = \frac{1}{2}mv^2 -\frac{1}{2}mu^2 = \frac{1}{2}m(v-u)^2 = \frac{1}{2}m(v-0)^2 = \frac{1}{2}mv^2

From the solution above, the magnitude of the change in velocity experienced by 10 kg ball is higher than 5 kg ball.

Hence, The magnitude of the change of velocity the 5-kg ball experiences is less than that of the 10-kg ball

4 0
3 years ago
The ____ approach to managing innovation assumes that innovation is a predictable process made up of a series of steps and that
dybincka [34]
The "generational change"  approach to managing innovation assumes that innovation is a predictable process made up of a series of steps and that compressing the time ittakes to complete those steps can speed up innovation.
5 0
3 years ago
True or False<br><br> An object will slow down and stop as long as no forces act upon it
My name is Ann [436]

Answer:

false

Explanation:

Understand Newton’s first law of motion. Experience suggests that an object at rest will remain at rest if left alone, and that an object in motion tends to slow down and stop unless some effort is made to keep it moving. An object will go on forever if there were no forces to act upon it. In space, a rocket will go forever at the speed it projects.

5 0
3 years ago
Read 2 more answers
A student heats a liquid on a burner. What happens to the portion of liquid that first begins to warm? Check all that apply.
kherson [118]

Answer:

The answers are options B,D and E

Explanation:

B) The particles in the liquid are slowly overcoming the forces of attraction and spreading out due to the thermal energy they are absorbing. This makes the liquid less dense as it slowly changes into a gas after reaching its boiling point.

D) The particles start absorbing the energy form the surroundings as latent heat of evaporation. They need this energy to overcome the strong forces of attraction between particles to change into the gaseous state

E) The particles have spaced out due to the thermal energy absorbed, making the liquid lighter and it rises upwards.

5 0
3 years ago
The total surface area of the human body is 1.20 m2 and the surface temperature is 30∘C=303∘K. If the surroundings are at a temp
zalisa [80]

To solve this problem we must consider the expressions of Stefan Boltzmann's law for which the rate of change of the radiation of energy H from a surface must be

H = Ae\sigma T^4

Where

A = Surface area

e = Emissivity that characterizes the emitting properties of the surface

\sigma = Universal constant called the Stefan-Boltzmann constant (5.67*10^{-8}m^{-2}K^{-4})

T = Absolute temperature

The total heat loss would be then

Q = H_2 -H_1

Q =Ae\sigma T_2^4-Ae\sigma T_1^4

Q = Ae\sigma (T_2^4-T_1^4)

Q = (1.2)(1)(5.67*10^{-8})(303^4-280^4)

Q = 155.29J

Therefore the net rate of heat loss from the body by radiation is 155.29J

8 0
3 years ago
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