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RSB [31]
3 years ago
14

HURRY PLEASE!! find the lcm of 3x^2-6x-24 and 9x^2-36

Mathematics
2 answers:
mr_godi [17]3 years ago
7 0

Answer:

9(x - 2)(x - 4)(x + 2)

Step-by-step explanation:

3x^2 - 6x - 24

= 3(x^2 - 2x - 8)

= 3(x - 4)(x + 2)

9x^2 - 36

= 9(x^2 - 4)

= 9(x - 2)(x+ 2)

So the LCM is:

9(x - 2)(x - 4)(x + 2)

Mrac [35]3 years ago
4 0

Answer:

yeeeeeeeeeeee

Step-by-step explanation:

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kondor19780726 [428]
The answer is f(x) will eventually exceed g(x) because f(x) is an exponential function.
6 0
3 years ago
A coin purse contains d dimes and q quarters.There are 20 coins in the purse and the total value of the coins is $4.25.which sys
mel-nik [20]
25q + 10d = 425
q + d = 20

First thing's first, picture 4 quarters. Do you know how much these 4 quarters are worth? Obviously, you'd answer one dollar, but take the time to think about how exactly you came up with this answer.

"Well, it's simple," you might think, "Multiply 0.25 by 4."

Similar to this train of thought, the first equation is formulated by doing exactly that. 'q' represents an unknown number of quarters, and 'd' an unknown number of dimes. We use 25q and 10d, because, well, we're multiplying their value by the number of coins. They're equivalent to 425 because the 20 unknown coins make $4.25 (I converted it to cents to get rid of the pesky decimals, but if you want to keep it as dollars that works too).

Because the equation states that there are 20 coins in total, we know that we can make the equation 'q + d = 20' since there are 20 quarters and dimes in total.

Let me know if you need any further explanation :)
-T.B.
3 0
3 years ago
Read 2 more answers
Please help and thank you
mamaluj [8]

Answer:

C

Step-by-step explanation:

a is defined first as 5. So a = 5.

b is defined after the circle b = -2

a^2 = 5^2 = 25

B^4 =(- 2)^4 = 16

Therefore sqrt(a^2 * b^4) = sqrt(25 * 16) = sqrt(400) = 20

The answer is C

5 0
3 years ago
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What's 6+□=3+□ please help me I really need the answer
Alexeev081 [22]
6+3 = 3+6 is your answer
8 0
3 years ago
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For a boat to float in a tidal bay, the water must be at least 2.5 meters deep. The depth of water around the boat, ????(????),
Effectus [21]

Answer:

a. Period, T = 12.57 hours. b. Latest time = 294.16 hours, 6 a.m 12 days later

Step-by-step explanation:

For a boat to float in a tidal bay, the water must be at least 2.5 meters deep. The depth of water around the boat, d(t), in meters, where t is measured in hours since midnight, is d(t) = 5 + 4.6sin(0.5t). (a) What is the period of the tides in hours? (b) If the boat leaves the bay at midday, what is the latest time it can return before the water becomes too shallow?

a. The period, T of the tides is gotten from ω = 2π/T, where ω is the angular frequency of the wave and T its period. Comparing the sine part of equation of the tides with the general equqtion of a sine wave, Asinωt, thus Asinωt = 4.6sin(0.5t),

so ω = 0.5 rad/s.

Equating this to 2π/T implies

0.5 = 2π/T

therefore, T = 2π/0.5 = 12.566 hours ≈ 12.57 hours

b. The tide becomes too low if it is less than 2.5 m i.e d(t) < 2.5 m. So, equating d(t) as 2.5 in the tidal equation, we have d(t) = 5 + 4.6sin(0.5t).

2.5< 5+ 4.6sin(0.5t)

2.5-5 < 4.6sin(0.5t)

-2.5 < 4.6sin(0.5t)

-2.5/4.6 < sin(0.5t)

-0.543 < sin(0.5t)

sin⁻¹(-0.543)<0.5t

-32.92<0.5t. Since we cannot have negative time, we add 180 to -32.92 to give 147.08

147.08<0.5t

t>147.08/0.5=294.16 hours

So, if t is greater than 294.16 hours, the water will be shallow. That is, below 2.5 m. which is 12 days 6hours 8 min 38 s which is 6 a.m 12 days later

3 0
2 years ago
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