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bixtya [17]
3 years ago
15

How to write the linear function passing through the points (3,-5) and (-8,-5)

Mathematics
1 answer:
enot [183]3 years ago
8 0

Check the pictrue below.

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PLS PLS HELP ILL MARK U BRAINLIEST
Inga [223]

Answer:

-16y+3y i BELIEVEEE

Step-by-step explanation:

3 0
2 years ago
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The probability that Josslyn is on time for a given class is 99 percent. If there are 32 classes during the semester, what is th
Gre4nikov [31]

Answer:

The best estimate is 32 out of 32 times, she will be early to class

Step-by-step explanation:

The probability of being early is 99% = 99/100 = 0.99

So out of 32 classes, the best estimate for the number of times she will be early to class will be;

0.99 * 32 = 31.68

To the nearest integer = 32

4 0
2 years ago
Simplify (2x-2)/(x-1). Show work.
kozerog [31]

Answer:

\frac{(2x - 2)}{(x - 1)}

=  \frac{2(x - 1)}{x - 1}

= 2

3 0
3 years ago
g Annual starting salaries in a certain region of the U. S. for college graduates with an engineering major are normally distrib
algol13

Answer:

The probability that the sample mean would be at least $39000 is of 0.8665 = 86.65%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean $39725 and standard deviation $7320.

This means that \mu = 39725, \sigma = 7320

Sample of 125

This means that n = 125, s = \frac{7320}{\sqrt{125}}

The probability that the sample mean would be at least $39000 is about?

This is 1 subtracted by the pvalue of Z when X = 39000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{39000 - 39725}{\frac{7320}{\sqrt{125}}}

Z = -1.11

Z = -1.11 has a pvalue of 0.1335

1 - 0.1335 = 0.8665

The probability that the sample mean would be at least $39000 is of 0.8665 = 86.65%.

4 0
2 years ago
6-8x=7x-10x-24 solve for x
lana66690 [7]

Answer:

x = 6

Step-by-step explanation:

Let's solve your equation step-by-step.

6−8x=7x−10x−24

Step 1: Simplify both sides of the equation.

6−8x=7x−10x−24

6+−8x=7x+−10x+−24

−8x+6=(7x+−10x)+(−24)(Combine Like Terms)

−8x+6=−3x+−24

−8x+6=−3x−24

Step 2: Add 3x to both sides.

−8x+6+3x=−3x−24+3x

−5x+6=−24

Step 3: Subtract 6 from both sides.

−5x+6−6=−24−6

−5x=−30

Step 4: Divide both sides by -5.

−5x/-5 = -30 /-5

x=6

4 0
3 years ago
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