All categories

3 years ago

If two triangles are congruent, which of the following statements must be true?

Mathematics

2 answers:

PSYCHO15rus [73]3 years ago

7 0

Answer:

The correct options are A, B, C and D.

Step-by-step explanation:

A figure said to be congruent if:

Two figures are said to be congruent if they have same size and same shape.

If two figure are congruent that means the corresponding sides will also be congruent.

If two figure are congruent that means the the corresponding angles will also be congruent.

Now consider the provided option.

By the above definition it is clear that all the options are correct.

Hence, the correct options are A, B, C and D.

kobusy [5.1K]3 years ago

3 0

If the two triangles are congruent,
then all four choices are true.

You might be interested in

Find the constant of variation for the relation and use it to write an equation for the statement. Then solve the equation 7 If

Juliette [100K]

Answer:

The required constant of variation is 4 and the equation is y=4xz over w (over meaning a fraction)

I don't know if you need a explanation on how to do this, just let me know if so.

Step-by-step explanation:

7 0

2 years ago

Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.

Sindrei [870]

Answer:

a) $P(X=3) = 0.1$

b) $P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

c) $P(X=4) = 0.3$

d) $P(X=0) = 0.2$

e) $E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

f) $E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

Step-by-step explanation:

We have the following distribution

x 0 1 2 3 4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

$P(X=3) = 0.1$

Part b

We want this probability:

$P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

Part c

For this case we want this probability:

$P(X=4) = 0.3$

Part d

$P(X=0) = 0.2$

Part e

We can find the mean with this formula:

$E(X)= \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

Part f

We can find the second moment with this formula

$E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

4 0

3 years ago

Whats the pattern that comes. Next please help

guajiro [1.7K]

The answer is 176 and 16

6 0

3 years ago

Read 2 more answers

Someone help please. A sports website writing team tries to predict the number of visits to their site based on the number of po

dimaraw [331]

Answer:

The scatter plot shows a positive correlation because the number of website visit increases as the number of posts increases

Step-by-step explanation:

The scatter plot shows a positive correlation because the number of website visit increases as the number of posts increases

6 0

3 years ago

Alice's goal is to have $30 in her account. She starts with $24.60 from washing cars. She spends $8.25 at the movies. Then she e

bazaltina [42]

24.60 - 8.25 + 11.50 = 30

16.35 + 11.50 = 30

27.85 <span>≠ </span>30

Alicia does not have $30, she needs to earn 2.15 more dollars

3 0

4 years ago

Read 2 more answers