Listen to the three examples of sound and related spectrogram. Make one observation about each of the three spectrograms.

Anemia is a medical condition in which the affected person lacks enough red blood cells. What two effects will such a condition

Nana76 [90]

Answer:

E. The patient will have increased platelets in the body

C. The patient will have a reduced oxygen supply to the cells

i did the test

Explanation:

3 0

3 years ago

Read 2 more answers

Which statement explains why Jayden’s reasoning is correct?

Yanka [14]

Answer:

lol

Explanation:

you gave no statements)

7 0

3 years ago

What is intramembranous ossification? What is intramembranous ossification? the formation of bone from preexisting hyaline carti

Aneli [31]

Answer:

The correct option is formation of bone from within fibrous membranes.

Explanation:

The process of intramembranous ossification results in the production of bones from the fibrous membranes. The mesenchymal cells get differentiated into different kinds of osteoblasts. The process of intramembranous ossification occurs in the skull. In other parts where bones are to be formed by this process, the mesenchymal cells get converted into cartilage first. The cartilage will then be converted or replaced into bones.

Bones at the base of the skull and the long bones are produced by endochondral ossification.

5 0

4 years ago

A new kind of pet is in the market has fur color that is regulated by 5 unlinked genes F, G, H, I and J which are enzymes. Each

enot [183]

Answer:

Pathway 2 will be correct with an Orange fur animal with Ff Gg Hh Ii Jj genotype.

Explanation:

Pathway 2 will produce both Red and yellow color and according to the question, both red and yellow color will end up with having Orange fur color. So, pathway 2 is correct.
Orange color fur is desired here and F G H I J are dominant to f g h i and j. So, the most favorable genotype will be Ff Gg Hh Ii Jj.

6 0

4 years ago

The Aye-Aye exhibits incomplete dominance for eye color. In a population of Aye-Ayes there are red-eyed individuals exhibiting t

VMariaS [17]

Answer:

196.8

Explanation:

In a population of Aye-Ayes there are red-eyed individuals exhibiting the dominant phenotype -----i.e RR

yellow-eyed individuals exhibiting the recessive phenotype ----- i.e rr

in the next generation, we will have the following offspring

R R

r Rr Rr

All the offspring are heterozygous in nature.

Now, the question goes further by saying, if there are 66 yellow-eyed individuals in the current population of 459, i.e (q² =66)

How many would be expected to exhibit the heterozygous phenotype in the next generation which will consist of 410 total individuals.

In solving Hardy-Weinberg question, we use the following equation below.

p + q = 1

p² + 2pq + q² = 1

where;

p = the frequency of the dominant allele

q = the frequency of the recessive allele

p² = the frequency of individuals with homozygous dominant phenotype

2pq = the frequency of individuals with heterozygous phenotype

q² = frequency of individuals with the homozygous recessive phenotype

Now, If In the next generation, the total population = 410

and q² (yellow-eyed individuals that are recessive in nature) = 66

then; q²= $\frac{individuals with recessive phenotype}{total population}$

q² = $\frac{66}{410}$

q² = 0.16

q = $\sqrt{0.16}$

q = 0.4

Since q = 0.4, we can easily get p by using the formula above:

p + q = 1

p = 1 - q

p = 1 - 0.4

p = 0.6

∴ Since we've known our p and q , we can easily determine how many would be expected to exhibit the heterozygous phenotype in the next generation.

2pq = 2 ( 0.6 × 0.4)

= 2 ( 0.24)

= 0.48

2pq = $\frac{individuals with heterozygous phenotype}{total population}$

0.48 = $\frac{x}{410}$

x = 0.48 × 410

x = 196.8 individuals

4 0

3 years ago