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vladimir2022 [97]
3 years ago
5

Which formula would allow you to calculate the area of a circle

Mathematics
2 answers:
alekssr [168]3 years ago
8 0

The formula for the area of a circle is A= π r^2

mezya [45]3 years ago
5 0

Answer:

rpi^2 or pir^2

Step-by-step explanation:

radius times pi to the second

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In the polynomial below, what number should replace the question mark to produce a difference of squares? x2 + ?x - 49
shutvik [7]
We are asked to find unknown or the missing number to complete the polynomial given in the problem which is x² + ?x -49. First, let us equate the number to be equal to zero such as it would become x² + ?x - 49 = 0. Next, we need to find the factors such that it would produce a difference of squares and these two factors are a = +7 and b = -7. Hence, the complete solution is shown below:
(x + 7) (x-7) = 0
perform distribution and multiplication of terms such as shown below:
x² + 7x - 7x - 49 = 0
Combine the same term such as we can either add or subtract +7x to -7x and the result will be equal to 0x.
 x² + 0x - 49 = 0

Therefore, the missing number is 0. The answer is 0 which will result to x² +0x - 49.
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Lunna [17]
X=36 because 1/3 times 36 equals 12
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A sine function is transformed such that it has a single x-intercept in the interval (0,pi), a period of pi and a y-intercept of
Alex787 [66]
Just to make sure we're using the same language, I'm going to use the function form of:

y = A\sin(kx) + h

[] I would agree that k = 2, since the period is only half as long as a normal sine function. So, we so far, have y = A sin(2x) + h. We still need to find A and h.

[] The y-intercept is 3. Remember that the y-intercept happens when x = 0. So, plugging in x = 0 into our formula, we have: 3 = A sin(2*0) + h. In other words, 3 = A sin(0) + h = 0 + h = h. So, we now know that h = 3. The formula is now y = A sin(2x) + 3.

[] Finally, there is a single x-intercept. Picture what the sine function looks like right now, it is floating in the air around y = 3. We need to stretch it vertically until it just grazes the x-axis. 

If A = 1, then our sine function bounces between 2 and 4 (+/- 1 around h = 3). But that doesn't touch 0, so no good.

If A = 2, then our sine function bounces between 1 and 5 (+/- 2 around h = 3). Again, not quite touching 0 yet.

The answer should be A = 3, then our sine function bounces between 0 and 6 (+/- 3 around h = 3).

The final formula is y = 3 sin(2x) + 3.
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