During a scientific study a hypotheses is generally modified or discarded
so for first blank the answer is hypotheses
Now in case of phlogiston theory it was assumed that when a substance catches fire it evolve certain substances known as phlogiston which was later on discarded as there is no such particle. Infact a substane undergoing oxidation may gain weight
Hence in second blank the answer is new evidence didn’t support it,
Answer:
61.3 g/mol
Step-by-step explanation:
We can use the <em>Ideal Gas Law</em> to solve this problem:
pV = nRT
Since n = m/M, the equation becomes
pV = (m/M)RT Multiply each side by M
pVM = RT Divide each side by RT
M = (mRT)/(pV)
<em>Data:
</em>
m = 0.675 g
R = 0.0.083 14 bar·L·K⁻¹mol⁻¹
T = 0 °C = 273.15 K
p = 1 bar
V = 250 mL = 0.250 L
<em>Calculation:
</em>
M= (0.675 × 0.083 14 × 273.15)/(1 × 0.250)
M= 15.33/0.250
M= 61.3 g/mol
In a chemical change, the molecules in the reactants interact to form new substances. In a physical change, like a state change or dissolving, no new substance is formed.
hope this helped
Calculate the mass in grams of hydrogen chloride (HCl) that is formed when 5.6 L of molecular hydrogen, measured at TPE, reacts with an excess of gaseous molecular chlorine. MHCl = 36.5 g/mol
H2(g) + Cl2(g) → 2HCl(g)
Answer:
18.25g
Explanation:
The reaction equation is given as;
H₂ + Cl₂ → 2HCl
Given parameters:
Volume of hydrogen gas = 5.6L
The reaction occurs at STP.
Solution:
To solve this problem, let us find the number of moles of the hydrogen as;
At STP;
22.4L of a gas has 1 mole;
5.6L of Hydrogen as will have
= 0.25mole
From the balanced reaction equation;
1 mole of H₂ will produce 2 mole of HCl
0.25 mole of H₂ will produce 2 x 0.25 = 0.5mole of HCl
The mass of HCl';
Mass of HCl = number of moles x molar mass
Mass of HCl = 0.5 x 36.5 = 18.25g