Answer:
A. There was still 140 ml of volume available for the reaction
Explanation:
According to Avogadro's law, we have that equal volumes of all gases contains equal number of molecules
According to the ideal gas law, we have;
The pressure exerted by a gas, P = n·R·T/V
Where;
n = The number of moles
T = The temperature of the gas
R = The universal gas constant
V = The volume of the gas
Therefore, given that the volumes and number of moles of the removed air and added HCl are the same, the pressure and therefore, the volume available for the reaction will remain the same
There will still be the same volume available for the reaction.
1 mole of any gas under STP ----- 22.4 L
18.65 L*1 mol/22.4 L ≈ 0.8326 mol N2
Alkanes are hydrocarbons with straight, saturated branch chains. Ring-shaped hydrocarbons are cycloalkanes. Alkenes are branch chains that are straight and have at least one double bond. Alkynes are branch chains that are straight and have at least one triple bond.
<h3>What is Hydrocarbon ?</h3>
A hydrocarbon is an organic molecule in organic chemistry that is made completely of hydrogen and carbon. Examples of group 14 hydrides include hydrocarbons. The majority of hydrocarbons are colorless and hydrophobic, and their scents are either insignificant or best characterized by those of gasoline and lighter fluid.
Other side effects from certain hydrocarbons include coma, seizures, abnormal cardiac rhythms, and liver or kidney damage. Some solvents used in paints, dry cleaning, and household cleaning solutions are examples of items that contain hazardous hydrocarbons.
To know more about Hydrocarbon please click here : brainly.com/question/3551546
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Answer:
The pH of the buffer solution is 4.60.
Explanation:
Concentration of acid = ![[HC_2H_3O_2]=0.225 M](https://tex.z-dn.net/?f=%5BHC_2H_3O_2%5D%3D0.225%20M)
Concentration of salt = ![[KC_2H_3O_2]=0.162 M](https://tex.z-dn.net/?f=%5BKC_2H_3O_2%5D%3D0.162%20M)
Dissociation constant = 
The pH of the buffer can be determined by Henderson-Hasselbalch equation:
![pH=pK_a+\log\frac{[salt]}{[acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D)
![pH=-\log[1.8 \times 10^{-5}]+\log\frac{0.162 M}{0.225 M}](https://tex.z-dn.net/?f=pH%3D-%5Clog%5B1.8%20%5Ctimes%2010%5E%7B-5%7D%5D%2B%5Clog%5Cfrac%7B0.162%20M%7D%7B0.225%20M%7D)
pH = 4.60
The pH of the buffer solution is 4.60.
