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3 years ago

ANSWER ASAP GIVING BRAINLIEST FIVE STARS AND A HEART! Btw this is 6th grade science!

Chemistry

1 answer:

AlexFokin [52]3 years ago

6 0

Answer:

Visible light.

Infrared waves.

X-rays.

Ultraviolet light.

Gamma rays.

Radio waves.

Microwaves.

Explanation:

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Best answer will be tagged brainliest.... no spamming pliz

grin007 [14]

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A. Chloride ions (CI)

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5 0

3 years ago

Describe how you could use two LB/agar plates, some E. coli, and some ampicillin to determine how E. coli cells are affected by

KiRa [710]

Answer:

For this experiment we are going to take plate 1 as the control plate, so, in it there will be just E. coli in LB/agar; in plate 2, we are going to put E. coli in LB/agar and some ampicillin. Then, we have to wait for the E. coli colonies to form. After a while, the E. coli growth can be compared on both plates and determine if ampicillin affects or not the E. coli colonies.

Explanation:

If the ampicillin affects negatively E. coli colonies, we are going to observe that in plate 1 (control plate) there are E. coli colonies growing, but in plate 2, there is no E. coli colonies or, at least, there is a fewer number of colonies on it. If ampicillin doesn't affect E.coli, plate 1 (control) and plate 2 (ampicillin experiment) are going to be similar in number of colonies.

8 0

3 years ago

Name a possible product of this reaction in the presence of ether and AlCl3: methylbenzene + 1-chlorodecane.a. 1-methyl-2-decylb

Vikki [24]

Answer:

None of these

Explanation:

Friedel–Craft reaction is a reaction involves the attachment of substituents to the benzene ring.

Mechanism of the reaction of methylbenzene with 1-chlorodecane in the presence of ether and aluminum chloride :

Step -1 : Generation of stable carbocation.

Aluminium chloride acts as Lewis acid which removes the chloride ion from the alkyl halide forming carbocation. The primary carbocation thus formed gets rearranged to secondary primary carbocation which is more stable due to hyperconjugation.

Step-2: Attack of the ring to the carbocation

The pi electrons of the ring behave as a nucleophile and attacks the carbocation. Since, the group attached on the benzene is methyl (+R effect) , the attack is from the ortho and the para positions. Para product is more stable due to less steric hinderance.

The product formed is shown in mechanism does not mention in any of the options.

So, None of these is the answer

8 0

3 years ago

Read 2 more answers

How many moles of nitrogen gas will occupy a volume of .5L at 1.0atm and 298K

hammer [34]

Use the Ideal law Equation :

P.V= n.R.T

V = 0.5 L

P = 1.0 atm

R= 0.0821 L*atm/mol*K

n = R*T/P*V

P*V= n*R*T

1.0 * 0.5 = n *0.0821*298

0,5 = n* 24.4658

n = 0,5 / 24.4658

n =0.0204 moles

8 0

3 years ago

How many molecules are in 4HCl

Mnenie [13.5K]

4 molecules bc the coefficient is 4

8 0

3 years ago