Force or forces (in physics: net force)
Answer:
2442.5 Nm
Explanation:
Tension, T = 8.57 x 10^2 N
length of rope, l = 8.17 m
y = 0.524 m
h = 2.99 m
According to diagram
Sin θ = (2.99 - 0.524) / 8.17
Sin θ = 0.3018
θ = 17.6°
So, torque about the base of the tree is
Torque = T x Cos θ x 2.99
Torque = 8.57 x 100 x Cos 17.6° x 2.99
Torque = 2442.5 Nm
thus, the torque is 2442.5 Nm.
Answer:
Explanation:
mass of the coin m = 4.2 x 10⁻³ kg
radius of circular path r in which coin will move = 15 x 10⁻² m
coefficient of static friction μs = .7
at maximum angular velocity of ω , limiting force of friction will provide centripetal force to coin to rotate in circular path .
so centripetal force = frictional force
mω²r = μs x mg
ω²r = μs x g
ω² = μs x g / r
= .7 x 9.8 / 15 x 10⁻²
= 45.73
ω = 6.76 radian / s.
Are there any options or is it not a multiple choice question.