A 5.0 kg box slides down a 4.0 m long ramp that makes a 25 angle with the ground. If the coefficient of kinetic friction is 0.65
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Answer:
r = 22.3 cm
Explanation:
given,
angular speed = 45 rev/s
tangential speed = 63 m/s
length of the rotating string
angular velocity =
ω = 2 π N
ω = 2 π x 45
ω = 282.74 rad/s
we know,
v = r ω
r = 22.3 cm
The time between the successive crusts will give the time period of the wave.
So, the time period, T of the given wave is 0.2 s.
The frequency of a wave is the reciprocal of its time period. That is,
Frequency, ν =
=
= 5 Hz
Thus, the frequency of the given travelling periodic wave is 5 Hz.