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coldgirl [10]
3 years ago
7

A bird sitting on the limb of a tree is moving about 30 km/s with respect to the Sun. If the bird takes 1 second to drop down to

a worm below, the worm would be 30 km downrange from the bird when it reached the ground. This faulty reasoning is best countered with Newton's _____
Physics
1 answer:
Alexandra [31]3 years ago
7 0

Answer:

This faulty reasoning is best countered with Newton's First Law.

Explanation:

<em>Newton's First Law</em><em> states that every object or body will remain in its state, be it of rest or uniform motion, unless it is affected by a force. </em>

This means that even while sitting, we are all moving at extreme speeds with respect to the Sun, of approximately 30 km/s (<em>yes, including the bird and the worm)</em>, but we don't even notice because we are all moving at approximately the same speed, and we aren't being affected by a force strong enough that could change our state of being in said extreme speed with respect to the Sun (<em>that is, unless our Earth suddenly stopped moving around the Sun!</em>).

With that being said, when the bird drops down from the limb of the tree, it moves by "adding" a vertical speed from the tree to the ground, but, in reality, the bird is still moving at 30 km/s in a given axis with respect to the Sun, as well as the worm. Now, <em>since the worm didn't "add" a speed to move away from the bird</em> (or, at least, we assume that's what happened), the bird finally catches the worm.

To sum it all up: Yes, the worm still moves at 30 km/s with respect to the Sun, but the bird moves at the same speed, <em>PLUS </em>a given speed from the tree to the ground that helps it get to the worm.

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Find the position vector of a particle that has the given acceleration and the specified initial velocity and position. a(t) = 1
kondor19780726 [428]

Answer:

Explanation:

Given

Acceleration a(t)=14t\hat{i]+\sin (t)\hat{j}+\cos (2t)\hat{k}[/tex]

and v(0)=\hat{i}

r(0)=\hat{j}

we know a=\frac{\mathrm{d} v}{\mathrm{d} t}

\int dv=\int adt

v(t)=\int (14t\hat{i}+\sin (t)\hat{j}+\cos (2t)\hat{k})dt

v(t)=7t^2\hat{i}-\cos t\hat{j}+\frac{\sin (2t)\hat{k}}{2}+c

at t=0

v(0)=0-1\cdot \hat{j}+0+c

c=\hat{i}+\hat{j}

v(t)=(7t^2+1)\hat{i}+(1-\cos t)\hat{j}+\frac{\sin (2t)\hat{k}}{2}

and \frac{\mathrm{d} r}{\mathrm{d} t}=v(t)

\int dr=\int vdt

r(t)=\int ((7t^2+1)\hat{i}+(1-\cos t)\hat{j}+\frac{\sin (2t)\hat{k}}{2})dt

r(t)=(\frac{7}{2}t^3+t)\hat{i}+(t-\sin (t))\hat{j}+\frac{1}{2}\times (-\frac{1}{2}\cos 2t)\hat{k}+c_2

at t=0

r(0)=\hat{j}

r(t)=(\frac{7}{3}t^3+t)\hat{i}+(1+t-\sin t)\hat{j}+\frac{1}{4}(1-\cos 2t)\hat{k}

       

4 0
3 years ago
Momentum is usually not exactly conserved in a real world demonstration of momentum conservation. What is a possible reason for
Maksim231197 [3]

Answer:

For any collision occurring in an isolated system, momentum is conserved. The total amount of momentum of the collection of objects in the system is the same before the collision as after the collision.

Explanation:

Hope this helps

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3 years ago
Two wooden boxes of equal mass but different density are held beneath the surface of a large container of water. Box A has a sma
Novay_Z [31]

Answer:

Box A

Explanation:

Let mass of each wooden box =m

Density of box A=\rho_A

Density of box B =\rho_B

\rho_A

Density,\rho=\frac{m}{V}

V_A=\frac{m}{\rho_A}

V_B=\frac{m}{\rho_B}

Density of inversely proportional to volume.

The volume of box with smaller density is larger than the volume of box with large density.

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When the boxes are submerged under water.

Then, the buoyant force=\rho_l Vg

Where V=Volume of displace fluid.

\rho=Density of fluid

Buoyant force of box A=\rho_lV_Ag

Buoyant force of box  B=\rho_lV_Bg

Force=Buoyant force

ma_A=\rho_lV_Ag

ma_B=\rho_lV_Bg

Acceleration is directly proportional to volume.

Therefore,the box with large volume has greater acceleration.

Hence, the box A has greater acceleration.

5 0
3 years ago
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I would GUESS left, I really don’t know how you would learn something like this though because everything would probably move differently
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