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4 years ago

How could you predict that Jermaine's answer might be incorrect using your estimate

Mathematics

1 answer:

skelet666 [1.2K]4 years ago

6 0

I estimate that out of 100, Jermaine is either 50% correct or 50% incorrect

remain heartless

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A cow

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3 years ago

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2. What are the solutions to the equation 6x2 - X - 40 = 0?

Andreas93 [3]

Answer:

x=-28

Step-by-step explanation:

you multiply the number first

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3 years ago

To calculate the number of montly payments required to pay off a loan or meet an investment goal, use the _______ function.

soldier1979 [14.2K]

NPER function

Hope this helps... mark as Brainliest plz

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3 years ago

In which direction does the right side of this graph point? F(x)= -x^4-x^3+4x-2

suter [353]

Answer: Down

Step-by-step explanation:

We know that the graph of y = x 4 has both arms pointing up.

Now, since the leading coefficient of f ( x ) is negative, both arms are pointing down. Thus the right side is pointing down.

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3 years ago

For the following demand equation compute the elasticity of demand and determine whether the demand is elastic, unitary, or inel

adelina 88 [10]

Answer:

Demand is inelastic at p = 9 and therefore revenue will increase with

an increase in price.

Step-by-step explanation:

Given a demand function that gives <em>q</em> in terms of <em>p</em>, the elasticity of demand is

$E=|\frac{p}{q}\cdot \frac{dq}{dp} |$

If E < 1, we say demand is inelastic. In this case, raising prices increases revenue.
If E > 1, we say demand is elastic. In this case, raising prices decreases revenue.
If E = 1, we say demand is unitary.

We have the following demand equation $D(p)=-\frac{3}{4}p+29$ ; p = 9

Applying the above definition of elasticity of demand we get:

$E(p)=\frac{p}{q}\cdot \frac{dq}{dp}$

where

p = 9
q = $-\frac{3}{4}p+29$
$\frac{dq}{dp}=\frac{d}{dp}(-\frac{3}{4}p+29)$

$\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{d}{dp}\left(\frac{3}{4}p\right)+\frac{d}{dp}\left(29\right)\\\\\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{3}{4}$

Substituting the values

$E(9)=\frac{9}{-\frac{3}{4}(9)+29}\cdot -\frac{3}{4}\\\\E(9)=\frac{36}{89}\cdot -\frac{3}{4}\\\\E(9)=-\frac{27}{89}\approx -0.30337$

$|E(9)|=|\frac{27}{89}| < 1$

Demand is inelastic at p = 9 and therefore revenue will increase with an increase in price.

6 0

3 years ago