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Aneli [31]
3 years ago
8

3(y−1.5)=9.9–4.2y Please help. Solve for y

Mathematics
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

2

Step-by-step explanation:

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Let’s think about another type of scenario. What if you were told that a bracelet requires 10 beads and 10 minutes to make while
Georgia [21]

Answer:

$425

Step-by-step explanation:

Let x represent the number of bracelets made and let y represent the number of necklace made.

Since the craftsman has 1000 beads to work with, hence:

10x + 20y ≤ 1000    (1)

Also, the craftsman has 1600 minutes, hence:

10x + 40y ≤ 1600   (2)

From ploting equations 1 and 2 on the geogebra online graphing, we can see that the solution to the problem is (40, 30).

Since the bracelet costs $5 and a necklace costs $7.50, hence the maximum revenue is:

Revenue = 5x + 7.5y = 5(40) + 7.5(30) = $425

4 0
3 years ago
Can you help me find this answer
Georgia [21]

Answer:

y = 10m

Step-by-step explanation:

<u>Step 1:  Rewrite</u>

y = centimeters

y = millimeters * 10

y = 10m

Answer: y = 10m

6 0
3 years ago
Which of the following conversion ratios would you use to convert 780 mm to centimeters?
Westkost [7]
D. 1mm/10cm is the correct answer choice.
3 0
3 years ago
When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl
lara [203]

Answer:

A. P("Both Alice and Betty watch TV") = 12/25

B. P("Betty watches TV") = 12/25

C. P("Only Alice watches TV") = 3/25

Step-by-step explanation:

A. Because what we are told, Betty need that Alice turn on the TV, so, we first need the probability that she watches TV:

P(Alice)=3/5 (0.6)

And we know that:

P(Betty)=4/5 (0.8)

If we want the probability of both things happening at the same time (If you use a tree diagram, those events will be in the same branch), we proceed multiply them:

P("Both Alice and Betty watch TV") = 3/5 * 4/5 = 12/25

And this is the answer

B. Considering that Betty needs Alice to turn on the TV, the probability of Betty watching TV is the same as if she is with Alice.

P("Betty watches TV") = P("Both Alice and Betty watch TV") = 12/25

C. We use the same process as part A, but with a little difference. We now multiply for the probability that Betty does not watch TV (Because they still be in the same branch).

P("Betty does not watch TV") = 1 - P("Betty")

P("Betty does not watch TV") = 1 - 4/5

P("Betty does not watch TV") = 1/5

And the answer for part C is:

P("Alice watches TV without Betty") = 3/5 * 1/5 = 3/25

5 0
3 years ago
NEED HALP!!! Find the ordered pair $(s,t)$ that satisfies the system
satela [25.4K]

Answer:

(-8/7 ; 5/7)

Step-by-step explanation:

5t + 1/2s = 3 - - - (1)

3t - 6s = 9 - - - - - (2)

Multiply (1) by 12 and (2) by 1

Add the result to eliminate s

60t + 6s = 36

3t - 6s = 9

____________

63t = 45

t = 45 / 63

t = 5/7

Put t = 5/7 in either (1) or (2) to obtain the value of s

3(5/7) - 6s = 9

15/7 - 6s = 9

-6s = 9 - 15/7

-6s = (63 - 15)/7

-6s = 48/7

s = 48/7 * - 1/6

s = - 8/7

5 0
2 years ago
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