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Katarina [22]
3 years ago
8

Suggest one reason why the population of the woodland caribou has declined in the united states?

Biology
2 answers:
schepotkina [342]3 years ago
7 0
Well its most likely over hunted but if its endangered and not allowed to be hunted then it would be because of natural predators in the area being over populated and taking out the caribou to fast
blsea [12.9K]3 years ago
7 0
 
poachers take a big part of exsticed your average burger takes a little part because there is one less cow world but hunting an endangered specie  is not allowed to be hunted then it would be because of natural predators in the area being over populated and taking out the caribou to fast

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Which statement about natural selection is true?
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Explanation:

Environmental changes determine which animals survive

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DNA

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If the extracellular fluid has an excess of sodium ions, a. sodium ions move into cells b. intracellular fluid moves to the outs
Mandarinka [93]

Answer:

b. intracellular fluid moves to the outside of cells

Explanation:

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Considering the same population of cats as in Part A, what is the expected frequency of each genotype (TLTL, TLTS, TSTS ) based
zaharov [31]

Answer:

P = f(TLTL) = 0,16

H = f(TLTS) = 0,48

Q = f(TSTS) = 0,36

Explanation:

Hello!

The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values ​​can vary between 0 (absent allele) and 1 (fixed allele).

The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.

In this case, let's say:

f(TL) = p

f(TS) = q

p + q = 1

Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:

TL= 0,4

TS= 0,6

Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.

P = f(TLTL)

H = f(TLTS)

Q = f(TSTS)

Also P + H + Q = 1

And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:

p^{2} = f(TLTL)

2pq = f(TSTL)

q^{2} = f(TSTS)

So, if the population is in balance:

P = p^{2}

H = 2pq

Q = q^{2}

Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:

f(TLTL) = P = p^{2} = 0,4^{2} = 0,16

f(TLTS) = H = 2pq = 2*0,4*0,6 = 0,48

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