Answer:
The enrollment after 5 years is 10,724
Step-by-step explanation:
Generally, we can have the depreciation formula written as follows;
A = P(1 - r)^t
A is the number of enrollment in after a certain number of years t
P is the initial population which is 13,500
r is the rate of depreciation which is 4.5% = 4.5/100 = 0.045
t = 5 years
Substituting these values, we have it that;
A = 13,500(1-0.045)^5
A = 10,723.84
Answer:
1655
Step-by-step explanation:
Note the common difference d between consecutive terms of the sequence
d = - 1 - (- 4) = 2 - (- 1) = 5 - 2 = 8 - 5 = 3
This indicates the sequence is arithmetic with sum to n terms
= 
[ 2a₁ + (n - 1)d ]
Here a₁ = - 4, d = 3 and n = 90, thus
= 
[ (2 × - 4) + (89 × 3) ] = 45(- 8 + 267) = 45 × 259 = 1655
(-35-42-63)/7= (-140)/7=-20
Answer:
Gabby received
7 nickels
10 dimes
3 quarters
Step-by-step explanation:
Let
x----> the number of dimes
y----> the number of nickels
z---> the number of quarters
Remember that
1 dime=$0.10
1 nickel=$0.05
1 quarter=$0.25
we know that
0.10x+0.05y+0.25z=2.10 ------> equation A
x=y+3-----> equation B
z=y-4 -----> equation C
substitute equation B and equation C in equation A and solve for y
0.10(y+3)+0.05y+0.25(y-4)=2.10
0.10y+0.30+0.05y+0.25y-1=2.10
0.40y=2.10-0.30+1
0.40y=2.80
y=7 nickels
<em>Find the value of x</em>
x=y+3 -----> x=7+3=10 dimes
<em>Find the value of z</em>
z=y-4 -----> z=7-4=3 quarters
therefore
Gabby received
7 nickels
10 dimes
3 quarters
