Alright so, After rewriting the equation in a standard parabola, you get:
4 x 2 (y-0) =(x - 0)^2

Simplify it to get:
y= 0-p
y= 0-2

When you simplify that, your answer is:
y=-2

There you go folks, just saved you from reading that long paragraph of an answer the other guy has (I don't even think the answer is in there lol, I think he just wanted to help people solve it but still most people come here for answers)

4 0

2 years ago

Plzzzzzz helpppp

Vesna [10]

Answer:

a. the number of people at Friday's, Saturday's, and Sunday's performances combined.

Step-by-step explanation:

The reason this information is needed to solve this problem is because we are looking to find the number of people who attended Saturday's performance. Without any information on Saturday's performance, there is no way to solve the problem. We are given the number of people on Friday and Sunday's performance, but are not given a total amount of people on all performances.

7 0

3 years ago

Read 2 more answers

Mark the statement either true (in all cases) or false (for at least one example). If false, construct a specific example to sho

LUCKY_DIMON [66]

Answer with Step-by-step explanation:

We are given that $v_1,v_2,..,v_4$ are in $R^4$ and $v_1,v_2,v_3$ is linearly dependent then {v_1,v_2,v_3,v_4}[/tex] is also linearly dependent.

We have to find that given statement is true or false.

Dependent vectors:Dependent vectors are those vectors in which atleast one vector is a linear combination of other given vectors.

Or If we have vectors $x_1,x_2,....x_n$

Then their linear combination

$a_1x_1+a_2x_2+.....+a_nx_n=0$

There exist at least one scalar which is not zero.

If $v_1,v_2,v_3$ are dependent vectors then

$a_1v_1+a_2v_2+a_3v_3=0$ for scalars $a_1,a_2,a_3$

Then , by definition of dependent vectors

There exist a vector which is not equal to zero

If vector $v_3$ is a linear combination of $v_1\;and \;v_2$ , So at least one of vectors in the set is a linear combination of others and the set is linearly dependent.